Answer:
find your points
Step-by-step explanation:
Answer: x=-1 y=1
Step-by-step explanation:
solve y in 3+2x-y=0
y=3+2x
sub y=3+2x into -3 -7y=10x
-14x- 24= 10x
solve x in -14x-24=10x
x= -1
sub x= -1 into y =3+2x
y=1
so therefore x= -1 and y=1
Answer:
8
Step-by-step explanation:
The given expression is "three less than the quotient of ten and a number, increased by six”
The quotient of ten and a number increased by six is translated into mathematical expression as:
Three less than the quotient of ten and a number, increased by six is
When we substitute n=2, we get:
Divide to get:
Add to get:
Subtract
Answer:
142°
Step-by-step explanation:
It's important that you share the complete question. What is your goal here? Double check to ensure that you have copied the entire problem correctly.
The general equation of a circle is x^2 + y^2 = r^2. Here we know that the circle passes thru two points: (-3,2) and (1,5). Given that a third point on the circle is (-7, ? ), find the y-coordinate of this third point.
Subst. the known values (of the first point) into this equation: (-3)^2 + (2)^2 = r^2. Then 9 + 4 = 13 = r^2.
Let's check this. Assuming that the equation of this specific circle is
x^2 + y^2 = r^2 = 13, the point (1,5) must satisfy it.
(1)^2 + (5)^2 = 13 is not true, unfortunately.
(1)^2 + (5)^2 = 1 + 25 = 26 (very different from 13).
Check the original problem. If it's different from that which you have shared, share the correct version and come back here for further help.
