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3 years ago

Need help ASAP (Geometry) Fast!

Mathematics

1 answer:

suter [353]3 years ago

3 0

6) arc length = 2*PI*R* degree/360
arc length = 2 * PI * 3 * 65/360
= 6*PI x 65/360
= 13/12*PI

Answer = C

7) drawing the lines as given would make a T shape with B being the mid point, so the answer would be C

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Two vans leave a campground at the

klasskru [66]

Answer:

92 mph

Step-by-step explanation:

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2 years ago

a coin is tossed. find the probability of the coin landing on heads. write your answer as a fraction, percent, and decimal

inysia [295]

Since there are only two sides (heads & tails) to a coin:
Probability (as fraction) - 1/2
Probability (as percent) - 1/2 x 100 = 50%
Probability (as decimal) - 1 x 50/2 x 50 = 50/100 = 0.5

(P.S. Please mark this answer as the brainliest answer... Thank You)

6 0

2 years ago

Read 2 more answers

Read the instructions

nordsb [41]

Answer:

Step-by-step explanation:

$\frac{5x - 2}{4}+\frac{1}{2}=\frac{3y+2}{2}$

Multiply the equation by 4

$4*\frac{5x - 2}{4}+4*\frac{1}{2}=4*\frac{3y+2}{2}\\$

5x - 2 + 2 = 2*(3y + 2)

5x +0 = 2*3y + 2*2

5x = 6y + 4

5x - 6y = 4 --------------------(I)

$\frac{7y+3}{3}=\frac{x}{2}+\frac{7}{3}\\$

Multiply the equation by 6

$6*\frac{7y+3}{3}=6*\frac{x}{2}+6*\frac{7}{3}\\$

2*(7y + 3) = 3x + 2*7

14y + 6 = 3x + 14

14y = 3x + 14 - 6

14y = 3x + 8

-3x + 14y = 8 ------------------------(II)

Multiply equation (I) by 3 and equation (II) by 5 and then add

(I)*3 15x - 18y = 12

(II)*5 -15x + 70y = 40 {Now add}

52y = 52

y = 52/52

y = 1

Substitute y =1 in equation (I)

5x - 6*1 = 4

5x - 6 = 4

5x = 4 +6

5x = 10

x = 10/5

x = 2

7 0

3 years ago

All of the following are equivalent except O 4y O (4) 04.y O 4+ y

barxatty [35]

Answer:

I think it's 4y

Step-by-step explanation:

I think it's 4y is because if y = 0 they all work but 4y which is 0 while all the others are 4

3 0

2 years ago

Factor the polynomial F(x) =x^3-x^2-4x+4 completely.

Norma-Jean [14]

Answer:

Step-by-step explanation:

PART 1:

Possible roots by noticing the coefficient of first term:

x = 1, -1

PART 2:

1 | 1 -1 -4 4

1 0 -4

1 0 -4 0

The remainder is zero, hence one factor is (x-1)

PART 3:

$x^3-x^2-4x+4=(x^2-4)(x-1)\\\\x^3-x^2-4x+4=(x+2)(x-2)(x-1)$

PART 4:

$f(x)=(x+2)(x-2)(x-1)\\\\=(x^2-4)(x-1)\\\\=x^3-4x-x^2+4\\\\=x^3-x^2-4x+4$

6 0

2 years ago