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larisa [96]
3 years ago
15

Lamar's Coffee Shop makes a blend that is a mixture of two types of coffee. Type A coffee costs Lamar $4.40 per pound, and type

B coffee costs $5.60 per pound. This month, Lamar made 129 pounds of the blend, for a total cost of $658.80. How many pounds of type B coffee did he use?
Mathematics
1 answer:
Firdavs [7]3 years ago
5 0

Answer:

Lamar used 76 pounds of type B coffee

Step-by-step explanation:

Let x = the number of pounds of type A coffee

Let y = the number of pounds of type B coffee

Type A coffee costs Lamar $4.40 per pound, and type B coffee costs $5.60 per pound. This means total cost of type A coffee and type B coffee will be

$(4.4x + 5.6y)

This month, Lamar made 129 pounds of the blend, for a total cost of $658.80.

This means the sum of type A coffee and type B coffee for the month is 129 and the total cost is $658.80

The equations deducted are

x + y = 129 - - - - - - - - -1

4.4x + 5.6y = 658.80 - - - - - - - - - - 2

Substituting x = 129 - y in equation 2,

4.4(129 - y) + 5.6y = 658.80

567.6-4.4y + 5.6y = 658.80

-4.4y + 5.6y = 658.80 - 567.6

1.2y = 91.2

y = 91.2/1.2 = 76 pounds

x = 129-y = 129-76

= 53 pounds

Lamar used 76 pounds of type B coffee

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Otrada [13]
The second one. Cause the first one is .64$ per 4oz and the second one is .60$ per oz
8 0
3 years ago
Ricky race $640 in a charity walk last year this year he raised 15% more than he raised last year how much money did Ricky raise
Mashutka [201]
He raised $736.

One way is to multiply 640 x .15 = 96
Add 96 + 640 = 736
8 0
3 years ago
The braking distance, in feet of a car a Travling at v miles per hour is given.
irakobra [83]

The braking distance is the distance the car travels before coming to a stop after the brakes are applied

a. The braking distances are as follows;

  • The braking distance at 25 mph, is approximately <u>63.7 ft.</u>
  • The braking distance at 55 mph,  is approximately <u>298.35 ft.</u>
  • The braking distance at 85 mph,  is approximately <u>708.92 ft.</u>

b. If the car takes 450 feet to brake, it was traveling with a speed of 98.211 ft./s

Reason:

The given function for the braking distance is D = 2.6 + v²/22

a. The braking distance if the car is going 25 mph is therefore;

25 mph = 36.66339 ft./s

D = 2.6 + \dfrac{36.66339^2}{22} = 63.7 \ ft.

At 25 mph, the braking distance is approximately <u>63.7 ft.</u>

At 55 mph, the braking distance is given as follows;

55 mph = 80.65945  ft.s

D = 2.6 + \dfrac{80.65945^2}{22} \approx 298.35 \ ft.

At 55 mph, the braking distance is approximately <u>298.35 ft.</u>

At 85 mph, the braking distance is given as follows;

85 mph = 124.6555 ft.s

D = 2.6 + \dfrac{124.6555^2}{22} \approx 708.92 \ ft.

At 85 mph, the braking distance is approximately <u>708.92 ft.</u>

b. The speed of the car when the braking distance is 450 feet is given as follows;

450 = 2.6 + \dfrac{v^2}{22}

v² = (450 - 2.6) × 22 = 9842.8

v = √(9842.2) ≈ 98.211 ft./s

The car was moving at v ≈ <u>98.211 ft./s</u>

Learn more here:

brainly.com/question/18591940

8 0
2 years ago
A store has a 25\%25% off sale on coats. With this discount, the price of one coat is \$34.50$34.50. What is the original price
timama [110]

Answer:

$46

Step-by-step explanation:

A percent is a portion of 100. If  we receive 25% off then we pay 75% of the price. 100%-25%=75%. $34.50 is 75% of the original price. We find the new price through a proportion. A proportion is an equation where two ratios or fractions are equal. The ratios or fractions compare like quantities. For example, we will compare percent over percent to an equal ratio of $ to $.

\frac{75}{100} =\frac{34.50}{y}

I can now cross-multiply by multiplying numerator and denominator from each ratio.

75y=100(34.50)\\75y=3450

I now solve for y by dividing by 75.

\frac{75y}{75} =\frac{3450}{75} \\y= 46....

The original price was $46.


5 0
4 years ago
HELP ME PLEASE THIS IS REALLY IMPORTANT
andrezito [222]

Answer:

4

Step-by-step explanation:

COUNT ALL (16) DIVIDE BY 4

8 0
3 years ago
Read 2 more answers
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