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3 years ago

(x+1)^2 (x-4)(-2x+3) degree? Ld. Coef? y-int?

1 answer:

6 0

(x + 1)²(x - 4)(-2x + 3)
(x + 1)(x + 1)(x - 4)(-2x + 3)
(x² + x + x + 1)(-8x² + 3x + 8x - 12)
(x² + 2x + 1)(-8x² + 11x - 12)
(-8x^4 + 11x³ - 12x² - 16x³ + 11x² - 12x - 8x² + 11x - 12)
(8x^4 + 11x³ - 16x³ - 12x² + 11x² - 8x² - 12x - 11x - 12)
8x^4 - 5x³ + 15x² - 23x - 12

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Suppose that x is the probability that a randomly selected person is left handed. The value (1-x) is the probability that the pe

harina [27]

Answer:

The maximum variance is 250.

Step-by-step explanation:

Consider the provided function.

$V(x)=1000x(1-x)$

$V(x)=1000x-1000x^2$

Differentiate the above function as shown:

$V'(x)=1000-2000x$

The double derivative of the provided function is:

$V''(x)=-2000$

To find maximum variance set first derivative equal to 0.

$1000-2000x=0$

$x=\frac{1}{2}$

The double derivative of the function at $x=\frac{1}{2}$ is less than 0.

Therefore, $x=\frac{1}{2}$ is a point of maximum.

Thus the maximum variance is:

$V(x)=1000(\frac{1}{2})-1000{\frac{1}{2}}^2$

$V(x)=250$

Hence, the maximum variance is 250.

4 0

3 years ago

What is the least significant place in 0.1030

olchik [2.2K]

<h3>Least Significant Digit Place (LSD)</h3>

The Least Significant Digit Place, or LSD, is the digit with the least value in a string of numbers.

In 0.1030, there are 4 different significant places. 0.1030

For 0.1030, the least valuable digit place is the 0.1030. This is because this numeral appears at the end of the string, and is the least valuable.

5 0

2 years ago

Read 2 more answers

15 points, no messing around, please do it right

cupoosta [38]

Answer:

416 is your answer!!!

Step-by-step explanation:

mak me brainliest and add me as a fiend

8 0

2 years ago

a homeowner has just installed a swimming pool with a capacity of 3.5 x 10⁴ gallons.of the pool is initially empty, how many hou

labwork [276]

So I looked it up and it says something about 8 hours

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2 years ago

Problem PageQuestion An automobile manufacturing plant produced 34 vehicles today: 16 were motorcycles, 9 were trucks, and 9 wer

8_murik_8 [283]

Answer:

Probability that the first vehicle selected is a motorcycle and the second vehicle is a van is (24/187) or 0.1283.

Step-by-step explanation:

We are given that an automobile manufacturing plant produced 34 vehicles today: 16 were motorcycles, 9 were trucks, and 9 were vans.

Plant managers are going to select two of these vehicles for a thorough inspection. The first vehicle will be selected at random, and then the second vehicle will be selected at random from the remaining vehicles.

As we know that, Probability of any event = $\frac{\text{Favorable number of outcomes}}{\text{Total number of outcomes}}$

Now, Probability that the first vehicle selected is a motorcycle is given by;

= $\frac{\text{Number of motorcycles}}{\text{Total number of vehicles}}$

Here, Number of motorcycles = 16

Total number of vehicles = 16 + 9 + 9 = 34

So, Probability that the first vehicle selected is a motorcycle = $\frac{16}{34}$

Similarly, Probability that the second vehicle is a van is given by;

= $\frac{\text{Number of vans}}{\text{Total number of remaining vehicles}}$

Here, Number of vans = 9

And Total number of remaining vehicles after selecting one motorcycle = 34 - 1 = 33

So, Probability that the second vehicle selected is a van = $\frac{9}{33}$

Therefore, the probability that the first vehicle selected is a motorcycle and the second vehicle is a van = $\frac{16}{34}\times \frac{9}{33}$

= $\frac{24}{187}$ = 0.1283

5 0

2 years ago