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densk [106]
3 years ago
7

Solve using quadratic equations

Mathematics
1 answer:
olasank [31]3 years ago
7 0
4x² - 9x² + 5 = 0
4x² - 4x - 5x + 5 = 0
4x(x - 1) - 5(x - 1) = 0
(4x - 5)(x - 1) = 0

Set each binomial equal to zero. 

4x - 5 = 0
4x = 0 + 5
4x = 5
x = 5/4

x - 1 = 0
x = 0 + 1
x = 1

Your solutions are x = 1, 5/4
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When working with inequalities what do you do when its x squared > 16 and vice versa does the sign flip.
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x4

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Step-by-step explanation:

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x\sqrt{16}

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The contrary,

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7. If x can be any number, how many solutions are there for the equation? y = 7x – 1 * A. There are two solutions because there
Hitman42 [59]
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Lapatulllka [165]

Answer:

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