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3 years ago

Solve using quadratic equations

Mathematics

1 answer:

olasank [31]3 years ago

7 0

4x² - 9x² + 5 = 0
4x² - 4x - 5x + 5 = 0
4x(x - 1) - 5(x - 1) = 0
(4x - 5)(x - 1) = 0

Set each binomial equal to zero.

4x - 5 = 0
4x = 0 + 5
4x = 5
x = 5/4

x - 1 = 0
x = 0 + 1
x = 1

Your solutions are x = 1, 5/4

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PLEASE HELP ME:<br><br> Find the perimeter of the figure. Round to the nearest tenth.

Ksenya-84 [330]

Answer:

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Step-by-step explanation:

perimeter

perimeter = distance around two dimensional shape

= addition of all sides lengths

<h2>perimeter of the figure</h2><h2>= AB+BC+CD+AD</h2>

distance formula:

$d = \sqrt{( x_{2} - x_{1}) {}^{2} + ( y_{2} - y_{1}) {}^{2} }$

<h3>1) distance of AB</h3>

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(substitute the values into the distance formula)

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<h3>2) distance of BC</h3>

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<h3>3) distance of CD</h3>

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x1 = 3 x2 = -4

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$cd = \sqrt{( - 4 - 3) {}^{2} + ( - 3 - 1)) {}^{2} }$

$cd = \sqrt{( - 7) {}^{2} + ( - 4 ){}^{2} }$

$cd = \sqrt{65}$

CD = 8.1 units

<h3>4) distance of AD</h3>

A(-3,0) D(-4,-3)

x1 = -3 x2 = -4

y1 = 0 y2 = -3

$ad = \sqrt{( - 4 - ( - 3)) {}^{2} + ( - 3 - 0) {}^{2} }$

$ad = \sqrt{( - 1) {}^{2} + ( - 3) {}^{2} }$

$ad = \sqrt{10}$

AD = 3.2 units

<h2>perimeter of figure</h2>

= AB+BC+CD+AD

= 6.4 + 3.2 + 8.1 + 3.2

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