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3 years ago

6x−1/5=3/1 {8/3} {5/3} {3/2} {5/2}

Mathematics

1 answer:

pychu [463]3 years ago

8 0

Answer:

I got x = 8/15. you may have wrote something wrong in the equation if those are the answer options. but idk. hope this helps

Step-by-step explanation:

6x - 1/5 = 3/1

6x = 16/5

x = 8/15

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Kindly solve this question

Dmitry_Shevchenko [17]

Answer:

x=-1/7

Step-by-step explanation:

$\frac{3x-1}{3} -\frac{2x}{x-1} =x$

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$\frac{3x^2-4x+1}{3x-3} -\frac{6x}{3x-3} =x$

$\frac{3x^2-10x+1}{3x-3} =x$

$\frac{3x^2-10x+1}{3x-3} =\frac{x(3x-3)}{3x-3}$

$\frac{3x^2-10x+1}{3x-3} =\frac{3x^2-3x}{3x-3}$

$3x^2-10x+1=3x^2-3x$

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3 0

2 years ago

Whats the answer to this n how do I solve it

BigorU [14]

6/8 *3/2.
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18/16
Divide top and bottom by 2

9/8

8 0

3 years ago

When three professors are seated in a restaurant, the hostess asks them: "Does everyone want coffee?" The first professor says:

dalvyx [7]

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3 years ago

Nine is 12% of which number

Ksenya-84 [330]

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3 years ago

Hello I need help Finding the probability

Stolb23 [73]

Each petal of the region $R$ is the intersection of two circles, both of diameter 10. Each petal in turn is twice the area of a circular segment bounded by a chord of length $5\sqrt2$ , which implies the segment is subtended by an angle of $\dfrac\pi2$ . This means the area of the segment is

$\text{area}_{\text{segment}}=\text{area}_{\text{sector}}-\text{area}_{\text{triangle}}$
$\text{area}_{\text{segment}}=\dfrac{25\pi}4-\dfrac{25}2$

This means the area of one petal is $\dfrac{25\pi}2-25$ , and the area of $R$ is four times this, or $50\pi-100$ .

Meanwhile, the area of $G$ is simply the area of the square minus the area of $R$ , or $10^2-(50\pi-100)=200-50\pi$ .

So

$\mathbb P(X=R)=\dfrac{50\pi-100}{100}=\dfrac\pi2-1$
$\mathbb P(X=G)=\dfrac{200-50\pi}{100}=2-\dfrac\pi2$
$\mathbb P((X=R)\land(X=G))=0$ (provided these regions are indeed disjoint; it's hard to tell from the picture)
$\mathbb P((X=R)\lor(X=G))=\mathbb P(X=R)+\mathbb P(X=G)=1$

4 0

4 years ago