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Studentka2010 [4]
3 years ago
8

SOMEONE PLEASE HELP!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
kotykmax [81]3 years ago
7 0
What is it you need help with it’s not showing
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find the value of x2 values that separate the middle 90% from the rest of the distribution for 8 degrees of freedom
Anettt [7]

Answer:

With alpha 0.95 and 8 degrees of freedom χ²= 2.73

And with alpha 0.05 and 8 degrees of freedom χ²=15.51

Step-by-step explanation:

The significance level ∝ = 1- 0.9 = 0.1

But we need the area of the middle so we divide this significance level with 2

so that we get exactly the middle area .

Dividing 0.1/2= 0.05

So we will have two values for chi square

One with  0.9 + 0.05 = 0.95 alpha and one with 0.05 alpha . This is because the chi square is right tailed.

So with alpha 0.95 and 8 degrees of freedom χ²= 2.73

And with alpha 0.05 and 8 degrees of freedom χ²=15.51

This can be shown with a graph.

4 0
3 years ago
Mr. Gengel wants to make a shelf with boards that are 1 1/3 feet long. If he has
PilotLPTM [1.2K]

Answer:

At most Mr.Gengel can cut at most 13 pieces with half a foot left.

8 0
3 years ago
Factor the expression.<br><br> 3x + 21
Delicious77 [7]

Answer: 3  ( x + 7 )

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
If 28% of students in College are near-sighted, the probability that in a randomly chosen group of 20 College students, exactly
cluponka [151]

Answer: (D) 16%

Step-by-step explanation:

Binomial probability formula :-

P(x)=^nC_xp^x(1-p)^n-x, where n is the sample size , p is population proportion and P(x) is the probability of getting success in x trial.

Given : The proportion of students in College are near-sighted : p= 0.28

Sample size : n= 20

Then, the the probability that in a randomly chosen group of 20 College students, exactly 4 are near-sighted is given by :_

P(x=4)=^{20}C_4(0.28)^4(1-0.28)^{20-4}\\\\=\dfrac{20!}{4!16!}(0.28)^4(0.72)^{16}\\\\=0.155326604912\approx0.16\%

Hence, the probability that in a randomly chosen group of 20 College students, exactly 4 are near-sighted is closest to 16%.

7 0
3 years ago
1. Preliminaries Remember the setup: We (the RAF in World War II) want to know the number of warplanes fielded by the Germans. T
natima [27]

Answer:

N is a population parameter; the computation using an estimate of N is a statistic.

Step-by-step explanation:

A parameter is a measure of a population.  The number of warplanes fielded total is N; this makes it the population.  Thus N is a parameter.

A statistics is a measure of a sample.  The number computed using an estimate of N would be based on a sample, since it is an estimate of N; this makes it a statistic.

8 0
3 years ago
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