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alekssr [168]
3 years ago
6

I also have three large chocolate candy bars that are perforated into eight sections each. If I divide the bars into these secti

ons how many sections will I have altogether?
Also, can you explain how to draw a model of this problem?
Mathematics
1 answer:
solniwko [45]3 years ago
4 0

3*8 = 24

You will have 24 sections.

Take a rectangle.  Divide it into 8 equal sections

Repeat two more times.  That will give you 24 equal peices.

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PLEASE HELP ME I BEG
Kay [80]

Answer:

see explanation

Step-by-step explanation:

Using the trigonometric identity

• 1 + cot²x = csc²x

Consider the left side

csc^{4} x - cot^{4} x

Factorise as a difference of squares

= (csc²x - cot²x)(csc²x + cot²x)

= (1 + cot²x - cot²x)(csc²x + cot²x)

= csc²x + cot²x

= csc²x + csc²x - 1

= 2csc²x - 1 = right side ⇒ verified




8 0
3 years ago
What is the third angle in a triangle with two angles of 60* and 45*
REY [17]

The answer is 75° because all three angles of a triangle must add to 180°

6 0
3 years ago
Determine if the side lengths 6, 11, and 19 form a triangle. If it is a triangle, classify it by its sides.
Butoxors [25]
It is not triangle because the one side of triangle should be smaller than the other two sides
Let's check
6+11=17
17<19
Or
11+19=31
9<31
4 0
3 years ago
Kevin has $26 and wants to rent a bicycle. The bicycle rents for $6.25 per hour . How many hours can Kevin ride without owing mo
Alexeev081 [22]

Answer:

4 hours

Step-by-step explanation:

6.25X4=25 so he'll have an extra dollar


4 0
3 years ago
1. Find the sum of the measures of the interior angles of a convex 11-gon.
OleMash [197]

Answer:

The measure of the sum of interior angles of a 11-gon is 1620^{o}.

Each interior angle is approximately 147.273^{o}.

Step-by-step explanation:

A convex polygon has the measure of each interior angles to be less than 180^{o}.

But,

sum of interior angles of polygon = (n - 2) x 180^{o}

where n is the number of sides of the polygon.

For a convex 11-gon, we have;

sum of angles of a 11-gon = (11 - 2) x 180^{o}

                                         = 9 x 180^{o}

                                         = 1620^{o}

Sum of angles of a 11-gon = 1620^{o}

To check: convex polygons' interior angles are less than 180^{o}.

so that,

each interior angle of 11-gon = \frac{1620}{11}

                                        = 147.273^{o}

3 0
3 years ago
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