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4 years ago

Use the above figure to answer the question. What's the angle between the tangents at T in the figure?

Mathematics

1 answer:

Sav [38]4 years ago

8 0

Show me the figure and i can help you out

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There are 50 stars on each United States flag. Two flags have 100 stars. Three flags have 150 stars. The equation that describes

Stolb23 [73]

Answer:

50•x

Step-by-step explanation:

x=number of flags

50 times the number of United states flags

3 0

3 years ago

Read 2 more answers

Solve the given system of equations <br> 2x+8y=5<br> 24x-4y=-15

oee [108]

The value of x and y is y= 3/4 and x= -1/2

<h3>What is equation?</h3>

An equation is a mathematical expression that contains an equals symbol. Equations often contain algebra.

Given equations:

2x+8y=5........(1)

24x-4y=-15...........(2)

Multiply equation (1) by 12, we get

24x + 96y = 60.....(3)

From (2) and (3), we get

-4y-96y= -15-60

-100 y= -75

y= -75/-100

y= 3/4

and 2x+8y=5

2x + 8 (3/4) =5

2x + 6 = 5

2x= -1

x= -1/2

Learn more about his concept here:

brainly.com/question/11203869

#SPJ1

7 0

2 years ago

The image shows parallel lines cut by a transversal. The expressions represent unknown angle measurements. What is the value of

Triss [41]

Answer) C. 77
This picture shows how I got to the answer. You must set up the two expressions to equal each other and then solve for X

7 0

4 years ago

Find the length of the curve. R(t) = cos(8t) i + sin(8t) j + 8 ln cos t k, 0 ≤ t ≤ π/4

arsen [322]

we are given

$R(t)=cos(8t)i+sin(8t)j+8ln(cos(t))k$

now, we can find x , y and z components

$x=cos(8t),y=sin(8t),z=8ln(cos(t))$

Arc length calculation:

we can use formula

$L=\int\limits^a_b {\sqrt{(x')^2+(y')^2+(z')^2} } \, dt$

$x'=-8sin(8t),y=8cos(8t),z=-8tan(t)$

now, we can plug these values

$L=\int _0^{\frac{\pi }{4}}\sqrt{(-8sin(8t))^2+(8cos(8t))^2+(-8tan(t))^2} dt$

now, we can simplify it

$L=\int _0^{\frac{\pi }{4}}\sqrt{64+64tan^2(t)} dt$

$L=\int _0^{\frac{\pi }{4}}8\sqrt{1+tan^2(t)} dt$

$L=\int _0^{\frac{\pi }{4}}8\sqrt{sec^2(t)} dt$

$L=\int _0^{\frac{\pi }{4}}8sec(t) dt$

now, we can solve integral

$\int \:8\sec \left(t\right)dt$

$=8\ln \left|\tan \left(t\right)+\sec \left(t\right)\right|$

now, we can plug bounds

and we get

$=8\ln \left(\sqrt{2}+1\right)-0$

so,

$L=8\ln \left(1+\sqrt{2}\right)$ ..............Answer

5 0

3 years ago

10. If I is the midpoint of SU, find x.<br> 8x + 11<br> 12x – 1<br> S<br> U<br> 8x+1=RX-1

USPshnik [31]

Answer:

x = 3

Step-by-step explanation:

$8x + 11 = 12x - 1 \\ 8x - 12x = - 1 - 11 \\ - 4x = - 12 \\ x = 3$

3 0

3 years ago