Answer:
S is the limiting reagent.
Explanation:
To find the limiting reactant we must first write the balanced chemical reaction. It must be correctly balanced so that we can find the proper mole ratios.
2 S (s) + 3 O2 (g) + 4 NaOH (aq) → 2 Na2SO4 (aq) + 2 H2O (l)
After this we will convert our measurements to moles. For mass we do this by dividing by the molar mass.
2g ÷ 32.06 = 0.06238mol S
3g ÷ 32.00 = 0.09375mol O₂
Now that we have the moles of each of the reactants, we can multiply them by their mole ratio with a reactant.
0.06238mol S × 2/2 = 0.06238mol H2O
0.09375mol O₂ × 2/3 = 0.06250mol H2O
S is our limiting reagent because it makes the smaller amount of moles.
55.5 I think but I may be wrong
Answer: This law is sometimes referred to as the 'Avogadro's Hypothesis' or 'Avogadro's Principle'. This is an experimnetal gas law that is relating to the volume of gas to the amount of substance of gas that is present to the state. This law also states that ''Equal volumes of all gases, at the same temp. and pressure, have the equal amount of molecules.''.
I hope this helps you and good luck! ☺
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