No, the dilution does not change the number of moles dissolved
Explanation:
We can see that,
The molarity of the solution was 0.50 M
The volume of the solution is 10 ml.
No of moles of the solute was= volume * concentration
= 10 X 10^-3* 0.50
= 5*10^-3 moles
When the solution is diluted from 10 ml to 100ml, the molarity or concentration changes but number of moles remains constant.
The molarity of 100 ml solution will be
c=n/V
= 5*10^-3*/100*10^-3
= 0.05
when the solution is diluted to 100ml from 10 ml molarity changes from 0.5M TO 0.05 M
Answer:
The radioactive decay mode that does not result in a different nuclide is gamma decay. In gamma decay, the only product is a gamma ray photon.
Explanation:
Answer:
The specific heat of the mineral is 0.1272J/g°C
Explanation:
The sample is given energy to the calorimeter and the sample of water.
The energy released for the sample is equal to the energy absorbed for both the calorimeter and the water:
C(Sample)*m*ΔT = C(Calorimeter)*ΔT + C(water)*m*ΔT
<em>Where C is specific heat</em>
<em>m is mass of the sample and water</em>
<em>And ΔT is change in temperature</em>
<em />
C(Sample)*149g*(92.7°C-23.7°C) = 12.8J/K*(23.7°C-20.0°C) + 4.184J/g°C*81.4g*(23.7°C-20.0°C)
C(Sample)*10281g°C = 47.36J + 1260.1J
C(Sample) = 0.1272J/g°C
<h3>The specific heat of the mineral is 0.1272J/g°C</h3>
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