Network & internet connection
Answer:
To check if the year comes under each 100th year, lets check if the remainder when dividing with 100 is 0 or not.
Similarly check for 400th year and multiple 0f 4. The following C program describes the function.
#include<stdio.h>
#include<stdbool.h>
bool is_leap_year(int year);
void main()
{
int y;
bool b;
printf("Enter the year in yyyy format: e.g. 1999 \n");
scanf("%d", &y); // taking the input year in yyyy format.
b= is_leap_year(y); //calling the function and returning the output to b
if(b==true)
{
printf("Thae given year is a leap year \n");
}
else
{
printf("The given year is not a leap year \n");
}
}
bool is_leap_year(int year)
{
if(year%100==0) //every 100th year
{
if(year%400==0) //every 400th year
{
return true;
}
else
{
return false;
}
}
if(year%4==0) //is a multiple of 4
{
return true;
}
else
{
return false;
}
}
Explanation:
Output is given as image
Try reinstalling the app or check if your wifi connection is good, if everything’s good but the app still doesn’t work then just use the website
Answer:
Written using C++
/*Enter Your Details Here*/
#include<iostream>
#include<cmath>
using namespace std;
int main()
{
//1
float side;
cout<<"Enter the side of a square: ";
//2
cin>>side;
//3
float perimeter = 4 * side;
cout<<"The perimeter is "<<perimeter<<endl;
//4
float area = side *side;
cout<<"The area is "<<area<<endl;
//5
float diagonal = sqrt(2 * side * side);
cout<<"The length of the diagonal is "<<diagonal;
return 0;
}
Explanation:
<em>I've added the full source code as an attachment where I used more comments to </em><em>explain </em><em>difficult line</em>
Answer:
Travelling in time might sound like a flight of fancy, but some physicists think it might really be possible. BBC Horizon looked at some of the most promising ideas for turning this staple of science fiction into reality.
Explanation: