Y = mx + b
slope(m) = 3/2
(5,9)...x = 5 and y = 9
now we sub and find b, the y int
9 = 3/2(5) + b
9 = 15/2 + b
9 - 15/2 = b
18/2 - 15/2 = b
3/2 = b
so ur equation is : y = 3/2x + 3/2.........(3,a)....so x = 3
y = 3/2(3) + 3/2
y = 9/2 + 3/2
y = 12/2
y = 6
so ur missing value is 6...a (or y) = 6
1. 11; 4
2. -64; 81
3. X+5; x+22,500
4. -13; -3
5. 8
6. 56F; 6F
7. -29/10 or -2 and 9/10
8. >; <; <
9. -2/9
<span>Quartiles are generally more reliable for judging outliers than mean and standard deviations for 2 reasons. The mean is simply the average of all of the numbers, meaning that an outlier can easily be obscured by the masses. Standard deviation is a better method, however only going over by one standard deviation in either direction would also mask an outlier. A strong outlier however will pull a quartile farther in that direction than would normally be expected.</span>
I would try Khan Academy. He does very good explainations