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3 years ago

What would be the remainder ?

Mathematics

1 answer:

ruslelena [56]3 years ago

3 0

Answer:

Step-by-step explanation:

Given (x + h) is a factor of f(x) then f(- h) = 0

Given

p(x) = x³ - 4x² + ax + 20 , with (x + 1) as a factor then

p(- 1) = (- 1)³ - 4(- 1)² - a + 20 = 0 , that is

- 1 - 4 - a + 20 = 0

15 - a = 0 ( subtract 15 from both sides )

- a = - 15 ( multiply both sides by - 1 )

a = 15 , thus

p(x) = x³ - 4x² + 15x + 20

If p(x) is divided by (x + h) then p(- h) is the remainder, so

p(- 2) = (- 2)³ - 4(- 2)² + 15(- 2) + 20 , that is

- 8 - 16 - 30 + 20 = - 34 → A

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The points plotted below are on the graph of a polynomial. In what range of x-values must the polynomial have a root?

Kaylis [27]

I think it is E not very sure but try it

3 0

3 years ago

a coin will be tossed 10 times. Find the chance that there will be exactly 2 heads among the first five tosses and exactly 4 hea

777dan777 [17]

Answer:

The chance that there will be exactly 2 heads among the first five tosses and exactly 4 heads among the last 5 tosses is P=0.0488.

Step-by-step explanation:

To solve this problem we divide the tossing in two: the first 5 tosses and the last 5 tosses.

Both heads and tails have an individual probability p=0.5.

Then, both group of five tosses have the same binomial distribution: n=5, p=0.5.

The probability that k heads are in the sample is:

$P(x=k)=\dbinom{n}{k}p^k(1-p)^{n-k}=\dbinom{5}{k}\cdot0.5^k\cdot0.5^{5-k}$

Then, the probability that exactly 2 heads are among the first five tosses can be calculated as:

$P(x=2)=\dbinom{5}{2}\cdot0.5^{2}\cdot0.5^{3}=10\cdot0.25\cdot0.125=0.3125\\\\\\$

For the last five tosses, the probability that are exactly 4 heads is:

$P(x=4)=\dbinom{5}{4}\cdot0.5^{4}\cdot0.5^{1}=5\cdot0.0625\cdot0.5=0.1563\\\\\\$

Then, the probability that there will be exactly 2 heads among the first five tosses and exactly 4 heads among the last 5 tosses can be calculated multypling the probabilities of these two independent events:

$P(H_1=2;H_2=4)=P(H_1=2)\cdot P(H_2=4)=0.3125\cdot0.1563=0.0488$

7 0

2 years ago

Solve for d.<br> 19d -16d-d-d-1 = 12

Reika [66]

Answer:

d = 13

Step-by-step explanation:

19d - 16d - d - d - 1 = 12

19d + (-16 - 1d - 1d) - 1 = 12

19d + (--18d) - 1 = 12

19d - 18d - 1 = 12

1d = 12 + 1

d = 13

Check:

19*13 - 16*13 - 13 - 13 - 1 = 12

247 - 208 - 26 - 1 = 12

39 - 27 = 12

7 0

6 months ago

The graph of a proportional relationship passes through (12, 16)<br> and (1, y)<br> . Find y

k0ka [10]

Answer: The value of y is $\frac{4}{3}$ .

Explanation:

It is given that the graph of a proportional relationship passes through (12, 16)

and (1, y).

The graph of a proportional relationship means the x and y coordinates are in a proportion k. The equation of the graph is in the form of y=kx. Where k is the proportion factor.

It is given that the graph passing through (12,16).

$y=kx$