Answer:
4.8 points/minute
Step-by-step explanation:
Just divide total point over total minutes.
<span>If there has to be 2 men and 2 women, we know
that we must take a group of 2 men out of the group of 15 men and a group of 2
women out of the group of 20 women. Therefore, we have:
(15 choose 2) x (20 choose 2)
(15 choose 2) = 105
(20 choose 2) = 190
190*105 = 19950
Therefore, there are 19950 ways to have a group of 4 with 2 men and 2women.</span>
<span>If there has to be 1 man and 3 women, we know
that we must take a group of 1 man out of the group of 15 men and a group of 3
women out of the group of 20 women. Therefore, we have:
(15 choose 1) x (20 choose 3)
(15 choose 1) = 15
(20 choose 3) = 1140
15*1140 = 17100
Therefore, there are 17100 ways to have a group of 4 with 3 women and 1 man.</span>
<span>We now find the total outcomes of having a group
with 4 women.
We know this is the same as saying (20 choose 4) = 4845</span>
Therefore, there are 4845 ways to have a group of
4 with 4 women.
We now add the outcomes of 2 women, 3 women, and
4 women and get the total ways that a committee can have at least 2 women.
19950 + 17100 + 4845 = 41895 ways that there will
be at least 2 women in the committee
Answer is C. By solving x-y=-5 to x=-5+y and converting 2x + y = -1 into 2x + x + 5 = -1 the answer becomes -2 =x. By plugging that into 2 (-2) + y = -1, the answer is y=3. So your answer is C
Part A:
- Each dollar spent DOES appear to always have the same number of points.
This is correct because it has a set rate of 10 points per dollar.
- Predicted number of points spent for $9:
$9 * 10 = $90
Part B:
- It DOES appear to take the same amount of time to serve each customer.
This is correct because it has a set rate of 4 minutes per customer.
- Predicted number of customers served in 36 minutes: 36/4= 9 customers.
Hope this helps!
