First, you have to find the equation of the perpendicular bisector of this given line.
to do that, you need the slope of the perpendicular line and one point.
Step 1: find the slope of the given line segment. We have the two end points (10, 15) and (-20, 5), so the slope is m=(15-5)/(10-(-20))=1/3
the slope of the perpendicular line is the negative reciprocal of the slope of the given line, m=-3/1=-3
step 2: find the middle point: x=(-20+10)/2=-5, y=(15+5)/2=10 (-5, 10)
so the equation of the perpendicular line in point-slope form is (y-10)=-3(x+5)
now plug in all the given coordinates to the equation to see which pair fits:
(-8, 19): 19-10=9, -3(-8+5)=9, so yes, (-8, 19) is on the perpendicular line.
try the other pairs, you will find that (1,-8) and (-5, 10) fit the equation too. (-5,10) happens to be the midpoint.
Answer:
Step-by-step explanation:
so he spends : 1/5 , 1/2 , 1/10.....common denominator of 10
1/5 + 1/2 + 1/10 = 2/10 + 5/10 + 1/10 = 8/10 = 4/5
so he spends 4/5 of his income.
that means he saves : 1 - 4/5 = 5/5 - 4/5 = 1/5 <==
<span>21x+28=14
x= -2/3 or -0.666666666
</span><span>9x+12y=6
x=2/3 or .666666666
y=0</span>
Answer:
x = 15
Step-by-step explanation:
The exterior angle of a triangle is equal to the sum of the 2 opposite interior angles.
∠ KLM is an external angle of the triangle, thus
∠ KLM = ∠ JKL + ∠ KJL , substitute values
5x - 7 = x + 20 + 2x + 3
5x - 7 = 3x + 23 ( subtract 3x from both sides )
2x - 7 = 23 ( add 7 to both sides )
2x = 30 ( divide both sides by 2 )
x = 15
![\qquad \tt \rightarrow \:Domain = [-9, -1]](https://tex.z-dn.net/?f=%5Cqquad%20%5Ctt%20%5Crightarrow%20%5C%3ADomain%20%3D%20%5B-9%2C%20-1%5D)
![\qquad \tt \rightarrow \:Range = [-1 , 3]](https://tex.z-dn.net/?f=%5Cqquad%20%5Ctt%20%5Crightarrow%20%5C%3ARange%20%3D%20%5B-1%20%2C%203%5D)
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Domain = All possible values of x for which f(x) is defined
[ generally the extension of function in x - direction ]
Range = All possible values of f(x)
[ generally the extension of function in y - direction ]
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![\qquad \tt \rightarrow \: range= [ -1,3]](https://tex.z-dn.net/?f=%5Cqquad%20%5Ctt%20%5Crightarrow%20%5C%3A%20range%3D%20%5B%20-1%2C3%5D)
Answered by : ❝ AǫᴜᴀWɪᴢ ❞
