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tia_tia [17]
3 years ago
8

How many solution does this have and how do you solve it

Mathematics
1 answer:
Vadim26 [7]3 years ago
5 0

Answer:

Infinite solutions

Step-by-step explanation:

To determine the number of solutions a system has, you need its slope. If the slopes are the same, check if the equations are equivalent or not.

To find the slope, rearrange the equation to isolate "y", which makes it slope-intercept form y = mx + b.

"x" and "y" represent points on the line.

"m" represents the slope, which is how steep a line is.

"b" represents the y-intercept (where the graph hits the y-axis).

Isolate "y" in both equations:

x + 3y = 0

3y = -x        Subtract 'x' from both sides

y = -x/3        Divide both sides by 3.

y = -\frac{1}{3}x

The slope is -1/3.

9y = -3x

y = -3x/9        Divide both sides by 9

y = -\frac{3}{9}x        Reduce the fraction to lowest terms

y = -\frac{1}{3}x

The slope is -1/3, but the two equations are the same.

Since the equations are the same, or <u>equivalent</u>, the two lines are always touching. The solution of a system means where two lines intersect, or meet. Therefore, <u>there are infinite solutions</u>.

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8 0
2 years ago
2. Which of the following equations are perpendicular to 2y = -3x + 1 I. II. III. y=-x-1 - 2x + 3y = -5 2x + 3y = 2 (A) I only (
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The equation in given as ;

2y = -3x + 1

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For perperdicular lines , the product of their slopes = -1 .This means if the other line has a gradient of m2 then : m1 * m2 = -1

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i) y= 2/3 x - 1 the slope is 2/3

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m1 * m2 = -1 -------check the if this is true by using the two values of gradient as;

-3/2 * 2/3 = - 1 ------ This is true-----equation i

II.

-2x + 3y = -5

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y= 2/3 x -5/3 -----m2 here is 2/3

m1*m2 = -1

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iii)

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