Answer:
<em>Answer:</em> <em>A</em> 
Step-by-step explanation:
The HL Theorem states that if the hypotenuse and leg of one right triangle are congruent to the hypotenuse and leg of another right triangle, then the two triangles are congruent.
Triangles TRO and OMT share the hypotenuse, so the first part of the theorem is met.
Both triangles are right because they have an internal angle of 90°, so the second condition is also met.
Since there is no indication of any leg to be congruent to another leg, we need additional information to prove that both triangles are congruent.
One of these two conditions should be met:
Side TM is congruent to side OR, or
Side MO is congruent to side RT.
From the available options, only the first is correct.
Answer: A 
Answer:
See explanation
Step-by-step explanation:
Let 
be the number of students and 
be the number of adults on the show.
1. Tickets cost $15 for students, so x student tickets cost $15x.
Tickets cost $25 for adults, so y adult tickets cost $25y.
Total cost of all tickets is $(15x + 25y).
The charity show is conducted in order to raise at least $3,750, thus
2. The auditorium can accommodate up to 180 spectators, hence
3. We get the system of inequalities:
Plot all solutions sets to each inequality and the common region is the solution set to the system of inequalities. This region is not empty, so the charity will reach its goal. For example, if they sell 50 students tickets and 125 adult tickets, they will raise 
Answer:
c
Step-by-step explanation:
Multiplying 49 by 1/7 in the inverse operation of dividing it by 7, so they will both get the correct answer.
It’s add positive 2 every time I believe
if I’m wrong I’m so sorry and please tell me I’m wrong for other that have to use this.
If I’m right ya!! XD
Hope this helps you!
-Pam Pam
Answer:
Tn = 2Tn-1 - Tn-2
Step-by-step explanation:
Before we can generate the recursive sequence, we need to find the nth term of the given sequence.
nth term of an AP is given as:
Tn = a+(n-1)d
If a17 = -40
T17 = a+(17-1)d = -40
a+16d = -40 ...(1)
If a28 = -73
T28 = a+(28-1)d = -73
a+27d = -73 ...(2)
Solving both equations simultaneously using elimination method.
Subtracting 1 from 2 we have:
27d - 16d = -73-(-40)
11d = -73+40
11d = -33
d = -3
Substituting d = -3 into 1
a+16(-3) = -40
a - 48 = -40
a = -40+48
a = 8
Given a = 8, d = -3, the nth term of the sequence will be
Tn = 8+(n-1) (-3)
Tn = 8+(-3n+3)
Tn = 8-3n+3
Tn = 11-3n
Given Tn = 11-3n and d = -3
Tn-1 = Tn - d... (3)
Tn-1 = 11-3n +3
Tn-1 = 14-3n
Tn-2 = Tn-2d...(4)
Tn-2 = 11-3n-2(-3)
Tn-2 = 11-3n+6
Tn-2 = 17-3n
From 3, d = Tn - Tn-1
From 4, d = (Tn - Tn-2)/2
Equating both common difference
(Tn - Tn-2)/2 = Tn - Tn-1
Tn - Tn-2 = 2(Tn - Tn-1)
Tn - Tn-2 = 2Tn-2Tn-1
2Tn-Tn = 2Tn-1 - Tn-2
Tn = 2Tn-1 - Tn-2
The recursive formula will be
Tn = 2Tn-1 - Tn-2
