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ANTONII [103]
3 years ago
13

When a user, Belinda Lim, signs in to Windows, she cannot see her Documents folder in File Explorer and some of her Windows user

settings are lost. You suspect her user profile is corrupted. Which tool or method should you use first to investigate and/or solve the problem? Second?
[Check all that apply]

a. Check the C:\User\Belinda Lim\Documents folder.
b. Check the C:\Users\Belinda Lim\Documents folder.
c. Use the chkdsk command.
d. Use the sfc command.
Computers and Technology
1 answer:
SashulF [63]3 years ago
5 0

Answer:

The answer is "option b and c".

Explanation:

  • We know that all the program or task that is performed in the computer is stored in the computer memory that is available in the internal part that is C disk.
  • To check this user profile we first open the Command Prompt then we write that command "C:\Users\Belinda Lim\Documents folder" that checks the folder and to resolve this problem we use "chkdsk command".
  • The full form of chkdsk command is "check disk".This command checks a particular disc and, when necessary, repairs or recovers data on the disk. This command also points as "bad" any broken or defective areas on the disk and retrieves any information that is still unharmed.

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import java.util.Scanner;

public class JavaApplication81 {

   

   public static void main(String[] args) {

       Scanner s = new Scanner(System.in);

       System.out.println("Input the string");

       String as = s.nextLine();

       int cons = 0;

       int a = 0;

       int e = 0;

       int i = 0;

       int o = 0;

       int u = 0;

       int space = 0;

       int punc = 0;

       char c;

       int misc = 0;

       String punctuation = ".!,?";

       String consonants = "bcdfghjklmnpqrstvwxyz";

       for (int k = 0; k < as.length(); k++){

           c = as.charAt(k);

       if (Character.isWhitespace(c)){

           space ++;

       }

       else if (punctuation.indexOf(c) != -1){

           punc++;

       }

       else if (consonants.indexOf(c) != -1){

           cons++;

       }

       else if (c == 'a'){

           a++;

       }

       else if(c == 'e'){

           e++;

       }

       else if (c == 'i'){

           i++;

       }

       else if (c == 'o'){

           o++;

       }

       else if (c == 'u'){

           u++;

       }

       else{

           misc++;

       }

       

   }

       System.out.println(a+" a's");

       System.out.println(e+" e's");

       System.out.println(i+" i's");

       System.out.println(o+" o's");

       System.out.println(u+" u's");

       System.out.println(space+" spaces");

   

       System.out.println(punc+" punctuations");

       System.out.println(cons+" consonants");

       System.out.println(misc+" misc. (uppercase vowels, etc.");

   }

   

}

This is one example of how it could be done.

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Answer:

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