Answer:
a = - 3, a = 4
Step-by-step explanation:
Given f(x) = x² + 2 and g(x) = x + 14 , then
f(a) = a² + 2 and g(a) = a + 14
For f(a) = g(a) , then equate the right sides
a² + 2 = a + 14 ( subtract a + 14 from both sides )
a² - a - 12 = 0 ← in standard form
(a - 4)(a + 3) = 0 ← in factored form
Equate each factor to zero and solve for a
a + 3 = 0 ⇒ a = - 3
a - 4 = 0 ⇒ a = 4
Answer:
no
Step-by-step explanation:
Answer:
X= -10
Step-by-step explanation:
I'm assuming this is for apolynomial function. The question of whether a degreee is odd or even changes the look of a graph. An even-numbered degree forms a parabola, where (in the most basic form), the one minimum point (extrema) just touches the origin. An odd-numbered degree, in its most basic form, doesn't touch a point, it crosses it. It expands infinitely without extrema.
Let's assume you're just talking about quadratic functions (or [even] parabolic functions, to be more general), in which case something like x^2 (the simplest quadratic equation) and x^50 would have the same extreme minimum point.
Answer:
Associative property of addition: a+{b+c=}{a+b}+c