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Scorpion4ik [409]
3 years ago
15

How do you get the answer to a math problem -k+h+kh k=-5 h=-2

Mathematics
2 answers:
Aloiza [94]3 years ago
4 0

Answer:

Final answer is 13.

Step-by-step explanation:

Given expression is

-k+h+kh

We also have been given values of h and k as:

k=-5 h=-2

to simplify the given expression, we just need to plug the given values of k=-5 and h=-2 into -k+h+kh

-k+h+kh

=-(-5)+(-2)+(-5)(-2)

=5+(-2)+(-5)(-2)

=5-2+(-5)(-2)

=5-2+(10)

=5-2+10

=3+10

= 13

Hence final answer is 13.

dalvyx [7]3 years ago
3 0

Answer:

7

Step-by-step explanation:

you have to put the numbers in for the variables

-5+2+5(2)

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Given the circumference of a circle is 26 pi, what is the area of the circle? Show work. Leave answer in term of pi.
Ierofanga [76]

Answer:169pi

Step-by-step explanation:

Circumference(c)=26pi

Circumference(c)=2 x pi x radius(r)

26pi=2pi x r

Divide both sides by 2pi

26pi/2pi=(2pi x r)/2pi

13=r

Radius(r)=13

Area of circle=pi x r^2

area of circle=pi x 13^2

Area of circle=169pi

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3 years ago
6-1/3 divided by 1/4 equals?
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The answer will be -8
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Which shows the first step in the solution to the<br> equation log₂x + log₂(x - 6) = 4?
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log was used calculate big numbers before calculators

log is a re-arranged way to show a number with an exponent

example

log₂ 16 = 4 means 2^4 = 16

logx(Z) = y means x^y=Z

log(x-6)/log(2) + log(x)/log(2) = 4

(log(x-6)+ log(x))/log(2) = 4

(log(x-6)+ log(x)) = 4log(2)

(log(x-6)x) = log(16)

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6 0
1 year ago
In a survey of 2,000 people who owned a certain type of​ car, 900 said they would buy that type of car again. What percent of th
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3 years ago
Simplify (3v5+8v3−10v2)−(−12v5+4v3+14v2) . Write answer in standard form.<br> ​<br> ​
Tatiana [17]

Answer:

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Step-by-step explanation:

Distribute the Negative Sign:

=3v5+8v3−10v2+−1(−12v5+4v3+14v2)

=3v5+8v3+−10v2+−1(−12v5)+−1(4v3)+−1(14v2)

=3v5+8v3+−10v2+12v5+−4v3+−14v2

Combine Like Terms:

=3v5+8v3+−10v2+12v5+−4v3+−14v2

=(3v5+12v5)+(8v3+−4v3)+(−10v2+−14v2)

=15v5+4v3+−24v2

Answer:

=15v5+4v3−24v2

Hope this helps! :)

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