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3 years ago

A right triangle has side lengths AC = 7 inches, BC = 24 inches, and AB = 25 inches.

Mathematics

2 answers:

ikadub [295]3 years ago

7 0

Answer:

(C)

Step-by-step explanation:

It is given that a right triangle, ACB which is right angled at C has BC = 24 inches, and AB = 25 inches.

We know that m∠C=90°,

Using the trigonometry in ΔACB, we have

$sinB=\frac{AC}{AB}$

Substituting the given values, we get

⇒ $sinB=\frac{24}{25}$

⇒ $B=sin^{-1}(0.96)$

⇒ $B=73.7^{\circ}$

Also, $sinA=\frac{CB}{AB}$

Substituting the given values, we get

⇒ $sinA=\frac{7}{25}$

⇒ $A=sin^{-1}(0.28)$

⇒ $A=16.3^{\circ}$

Therefore, the measure of the angles in triangle ABC are m∠A ≈ 73.7°, m∠B ≈ 16.3°, m∠C ≈ 90°.

Thus, option C is correct.

rusak2 [61]3 years ago

3 0

m∠A =73.7°
m∠B = 16.3°
m∠C = 90°

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