Question

A right triangle has side lengths AC = 7 inches, BC = 24 inches, and AB = 25 inches.

Answer 1

Answer:

(C)

Step-by-step explanation:

It is given that a right triangle, ACB which is right angled at C has BC = 24 inches, and AB = 25 inches.

We know that m∠C=90°,

Using the trigonometry in ΔACB, we have

$sinB=\frac{AC}{AB}$

Substituting the given values, we get

⇒$sinB=\frac{24}{25}$

⇒$B=sin^{-1}(0.96)$

⇒$B=73.7^{\circ}$

Also, $sinA=\frac{CB}{AB}$

Substituting the given values, we get

⇒$sinA=\frac{7}{25}$

⇒$A=sin^{-1}(0.28)$

⇒$A=16.3^{\circ}$

Therefore, the measure of the angles in triangle ABC are  m∠A ≈ 73.7°, m∠B ≈ 16.3°, m∠C ≈ 90°.

Thus, option C is correct.

Answer 2

m∠A =73.7° 
m∠B = 16.3°
m∠C = 90°