which equation is the equation of the line in point slope form that has a slope of 12 and passes through the point (-1, 14)

Mathematics

1 answer:

Nostrana [21]4 years ago

5 0

Point slope from would be 12x-y+26=0.

Black is the equation, 12x-y+26=0.

Orange is y-14=12(x+1)
Blue is y-14=12(x-1)
Red is y+14=12(x-1)
Green is y-14=-12(x+1)

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SpyIntel [72]

Answer:

Factor

Step-by-step explanation:

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3 years ago

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George is 1.94 meters tall and wants to find the height of a tree in his yard. He started at the base of the tree and walked 10.

Free_Kalibri [48]

Draw a diagram to illustrate problem as shown below.

Let h = the height of the tree.

Because ΔABC ~ ΔADE, therefore
DE/BC = AD/AB

That is,
h/1.94 = (5.1 + 10.2)/5.1 = 3
h = 1.94*3 = 5.82 m

Answer: 5.82 m

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3 years ago

Emily is making bracelets for herself and 6 of her friends she needs 1/5 of a yard of string to make each bracelet. How much str

frosja888 [35]

10 feet of string to make all the bracelets.

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3 years ago

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Find the discriminant and determine the nature of the roots to the quadratic equation

Katen [24]

№17
$x^{2} +6x-7=0 \\ D=6 ^{2} -4*(-7)=36+28=64=8 ^{2} \\ \\ x_{1} = \frac{-6+8}{2} =1 \\ \\ x_{2} = \frac{-6-8}{2} =-7$
Answer: x₁ = 1
   x₂ = - 7

№18
$2 x^{2} -3x+4=3 \\ 2 x^{2} -3x+4-3=0 \\ 2 x^{2} -3x+1=0 \\ \\ D= -3 ^{2} -4*2=9-8=1 \\ \\ x_{1} = \frac{3+1}{2*2} = \frac{4}{4} =1 \\ \\ x_{2} = \frac{3-1}{2*2} = \frac{2}{4} =0.5$
Answer: x₁ = 1
     x₂ = 0,5.

№19
$2 x^{2} -4x-5=0 \\ D=-4 ^{2} -4*2*(-5)=16+40=56 \\ \\ x_{1}= \frac{4+ \sqrt{56} }{2*2} = \frac{4}{4} + \sqrt{ \frac{56}{16} } =1+ \sqrt{3.5} \\ \\ x_{2} = \frac{4- \sqrt{56} }{2*2} = \frac{4}{4} - \sqrt{ \frac{56}{16} } =1- \sqrt{3.5} 
$
Answer: x₁ = 1 + √3.5
     x₂ = 1 - √3.5

3 0

4 years ago

PLEASE HELP! WILL GIVE 70 POINTS!!

Tresset [83]

Answer:

$A=189\ mm^2$

Step-by-step explanation:

Surface Areas

Is the sum of all the lateral areas of a given solid. We need to compute the total surface area of the given prism. It has 5 sides, two of them are equal (top and bottom areas) and the rest are rectangles.

Computing the top and bottom areas. They form a right triangle whose legs are 4.5 mm and 6 mm. The area of both triangles is

$\displaystyle A_t=2*\frac{b.h}{2}=b.h=(4.5)(6)=27 mm^2$