Answer:
Your question it is your answer
Answer:
There are 6 dimes and 9 quarters.
Step-by-step explanation:
Represent the number of dimes and the number of quarters by d and q.
Then d + q = 15, or q = 15 - d.
Also, ($0.25)q + ($0.10)d = $2.85, or 5q + 2d = 57.
Substituding 15 - d for q, we get 5(15 - d) + 2d = 57, or
75 - 5d + 2d = 57, or
75 - 3d = 57, or
3d = 18. Thus, there are 6 dimes. Since q = 15 - d, q = 15 - 6 = 9.
There are 6 dimes and 9 quarters.
<span> 100 m / 50 s = 2 m/s = 2 *3600 / 1000 = 7.2 k/h
hope it helps :)</span>
In order to find height from where ball is dropped, you have to find height or h(t) when time or t is zero.So plug in t=0 into your quadratic equation:h(0) = -16.1(0^2) + 150h(0) = 0 +150h(0) = 150 ft is the height from where ball is dropped. When ball hits the ground, the height is zero. So plug in h(t) = 0 and solve for t.0 = -16.1t^2 + 15016.1 t^2 = 150t^2 = 150/16.1t = sqrt(150/16.1)t = ± 3.05Since time cannot be negative, your answer is positive solution i.e. t = 3.05
