May I please get the answer. not for homework or assignment.

You have one type of nut that sells for $3.00/lb and another type of nut that sells for $5.40/lb. You would like to have 7.2 lbs

brilliants [131]

Answer: 2.4 pounds of the type of nut that sells for $3.00/lb and 4.8 pounds of the type of nut that sells for $5.40/lb would be needed.

Step-by-step explanation:

Let x represent the number of pounds of the type of nut that sells for $3.00/lb that you would need.

Let y represent the number of pounds of the type of nut that sells for $5.40/lb that you would need.

You would like to have 7.2 lbs of a nut mixture. It means that

x + y = 7.2

The mixture would sell for $4.60/lb. It means that the cost of the mixture would be

4.6 × 7.2 = $33.12

This means that

3x + 5.4y = 33.12- - - - - - - - - 1

Substituting x = 7.2 - y Intl equation 1, it becomes

3(7.2 - y) + 5.4y = 33.12

21.6 - 3y + 5.4y = 33.12

- 3y + 5.4y = 33.12 - 21.6

2.4y = 11.52

y = 11.52/2.4

y = 4.8

x = 7.2 - y = 7.2 - 4.8

x = 2.4

3 0

3 years ago

Please help me

Virty [35]

Answer:

1) Step 3: S = $136.49 - $3.0625 × 1/4

2) By completing the operations within the parenthesis in Step 2, before multiplying the result by 1/4

Step-by-step explanation:

1) From the given information, we have;

The amount amount Maria earns as a pet sitter = $32.75

The number of weeks Maria worked as a pet sitter = 2 weeks

The amount Mariah previously saved = $70.99

The amount Maria spent = $12.25

The amount Mariah put in her savings account = 1/4 of the remaining (balance) money

Therefore, we have;

The amount placed in Mariah's savings account, S, is given as follows;

Step 1: S = [($32.75 × 2) + $70.99 - $12.25] × 1/4

Step 2: S = [($65.5 × 2) + $70.99 - $12.25] × 1/4

Step 3: S = [($136.49) - $12.25] × 1/4

Step 4: S = $124.24 × 1/4

Step 5: S = $31.06

The amount Mariah puts in her saving's account = $31.06 and the step Mariah first makes an error is Step 3 where what she put down was as follows;

Step 3: S = $136.49 - $3.0625 × 1/4

2) She can correct the error by completing the calculation of the operation within the parenthesis in Step 2, before multiplying by the factor 1/4.

6 0

3 years ago

Read 2 more answers

Pleaseeee help on question 3 and 5 pleaseeeee wuick thank youuuuuuuuu

elena55 [62]

Answer:

3a, 13cm 5, 1:200

Step-by-step explanation:

In the question 3 you just have to divide all of those numbers with that 5000, maybe also make them cm so it makes more sense. So 650m = 65000cm:5000= 13cm

then for the question 5, make the km to cm, so 4.2km would be 420000cm. Then you have to divide that 420000cm with the 21 cm, so 420000:21= 200. Then the scale should be 1:200

I had difficulties with these as well. If you need extra help with the task 3 please pm me :)

7 0

3 years ago

The weekly amount of money spent on maintenance and repairs by a company was observed, over a long period of time, to be approxi

bazaltina [42]

Answer:

$425.6 should be budgeted for weekly repairs and maintenance.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean $400 and standard deviation $20.

This means that $\mu = 400, \sigma = 20$

How much should be budgeted for weekly repairs and maintenance to provide that the probability the budgeted amount will be exceeded in a given week is only 0.1?

This is the 100 - 10 = 90th percentile, which is X when Z has a p-value of 0.9, so X when Z = 1.28.

$Z = \frac{X - \mu}{\sigma}$

$1.28 = \frac{X - 400}{20}$

$X - 400 = 20*1.28$

$X = 425.6$

$425.6 should be budgeted for weekly repairs and maintenance.

6 0

3 years ago

a total of 775 tickets were sold for the school play. they were either adult or student tickets. there were 75 more student tick

Olegator [25]

a + s = 775

s = a + 75 ; where a = adult tickets and s = student tickets

____________________________________________________________

Solve for s in the first equation. Subtract a from both sides.

s = 775 - a

Plug s into the second equation.

(775 - a) = a + 75

Add a to both sides.

775 = 2a + 75

Subtract 75 from both sides.

700 = 2a

Divide both sides by 2.

a = 350

____________________________________________________________

350 adult tickets were sold.

8 0

3 years ago