When you have a right triangle with 45 degrees as shown
the hypotenuse would be the length of the side times sqrt(2)
so the side length for this would be 4
Answer:
Elizibeth Cady Stanton
Step-by-step explanation:
Anthony and Elizabeth Cady Stanton formed groups to push for women's right to vote during the Industrial Revolution. It took a long time and a lot of work, but women finally gained the right to vote when the 19th Amendment was ratified in 1920.
![\Huge \underline {\mathcal {{{\color{orange}{108 \degree}}}}}](https://tex.z-dn.net/?f=%20%5CHuge%20%20%20%5Cunderline%20%7B%5Cmathcal%20%7B%7B%7B%5Ccolor%7Borange%7D%7B108%20%5Cdegree%7D%7D%7D%7D%7D%20)
Option ( A ) is the correct answer.
- Sum of all interior angle of a regular pentagon is 540°
- Number of edges in regular pentagon is 5.
- Number of vertices in regular pentagon is 5.
Answer:
True
x = 4.32 (2 dp)
Step-by-step explanation:
x³ - 5x = 59
x³ - 5x - 59 = 0
x = 4
4³ - 5(4) - 59 = -15
x = 5
5³ - 5(5) - 59 = +41
A change in sign indicates the existence of root between 4 and 5
Use iterative process to identify the root
x³ - 5x - 59 = 0
x³ = 5x + 59
x = (5x + 59)^⅓
Start at any x between 4 and 5
x(n+1) = (5x(n) + 59)^⅓
x0 = 4.8
x1 = 4.362070671
x2 = 4.323369309
x3 = 4.319915667
x4 = 4.319607202
x5 = 4.318579649
Clearly x is 4.32 (2 dp)
Answer:
C
Step-by-step explanation:
We have the equation:
![x^2-6x=10](https://tex.z-dn.net/?f=x%5E2-6x%3D10)
We can subtract 10 from both sides:
![x^2-6x-10=0](https://tex.z-dn.net/?f=x%5E2-6x-10%3D0)
Since this equation isn't factorable, we can use the quadratic formula:
![\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20x%3D%5Cfrac%7B-b%5Cpm%5Csqrt%7Bb%5E2-4ac%7D%7D%7B2a%7D)
In this case, <em>a</em> = 1, <em>b</em> = -6, and <em>c</em> = -10.
Substitute:
![\displaystyle x=\frac{-(-6)\pm\sqrt{(-6)^2-4(1)(-10)}}{2(1)}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20x%3D%5Cfrac%7B-%28-6%29%5Cpm%5Csqrt%7B%28-6%29%5E2-4%281%29%28-10%29%7D%7D%7B2%281%29%7D)
Simplify:
![\displaystyle x=\frac{6\pm\sqrt{76}}{2}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20x%3D%5Cfrac%7B6%5Cpm%5Csqrt%7B76%7D%7D%7B2%7D)
Note that:
![\sqrt{76}=\sqrt{4\cdot 19}=2\sqrt{19}](https://tex.z-dn.net/?f=%5Csqrt%7B76%7D%3D%5Csqrt%7B4%5Ccdot%2019%7D%3D2%5Csqrt%7B19%7D)
Hence:
![\displaystyle x=\frac{6\pm2\sqrt{19}}{2}=3\pm\sqrt{19}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20x%3D%5Cfrac%7B6%5Cpm2%5Csqrt%7B19%7D%7D%7B2%7D%3D3%5Cpm%5Csqrt%7B19%7D)
Therefore, our answer is C.