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2 years ago

13

Rachel saved money to buy art supplies. She used 1/3 of her savings to buy brushes. She used 3/5 of her savings to buy paint. Wh

at fraction of her savings does she have remaining

1 answer:

kifflom [539]2 years ago

3 0

Rachel saved enough money and she used 14/15

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How should 13,079 be written in in expanded form

Thepotemich [5.8K]

Answer:

10,000 + 3,000 + 70 + 9

Step-by-step explanation:

It will be 10,000 + 3,000 + 70 + 9

That is how expanded form works.

Hope it helps :)

If you have any questions ask me.

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1 year ago

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The two triangles shown below are simiar. Which statement is true of the transformation from ABC to A' B' C'

AfilCa [17]

Answer: Thus when transforming from ABC to A'B'C', the lengths are scaled by a factor of 0.5 .

Step-by-step explanation:

Since the triangles are similar, the ratio of their sides are equal.

And we can count the number of blocks over which AC and A'C' is drawn and take them to be their length,

Therefore,

AC = 16

A'C'= 8

Thus when transforming from ABC to A'B'C', the lengths are scaled by a factor of 0.5 .

Measuring the tans of the angles by taking the ratio of opposite by adjacent, we get,

tanA = $\frac{10}{4}$

tanA'= $\frac{5}{2}$

which means tanA= tanA'

The angles do not change.

Thus when transforming from ABC to A'B'C', the lengths are scaled by a factor of 0.5 .

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2 years ago

Are these answers right? Questions are below!

Ipatiy [6.2K]

Answer:

8 yes

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2 years ago

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Divide and Round your answer to the nearest hundredth: 32.503/4.9

timurjin [86]

Answer:

6.63

Step-by-step explanation:

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2 years ago

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A teacher teaches two classes with 8 students each. Each student has a 95% chance of passing their class independent of the othe

dsp73

Answer:

0.4466 = 44.66% probability that, in exactly one of the two classes, all 8 students pass.

Step-by-step explanation:

For each student, there are only two possible outcomes. Either they pass, or they do not. The probability of an student passing is independent of other students, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Probability that all students pass in a class:

Class of 8 students, which means that $n = 8$

Each student has a 95% chance of passing their class independent of the other students, which means that $p = 0.95$

This probability is P(X = 8). So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 8) = C_{8,8}.(0.95)^{8}.(0.05)^{0} = 0.6634$

Find the probability that, in exactly one of the two classes, all 8 students pass.

Two classes means that $n = 2$

0.6634 probability all students pass in a class, which means that $p = 0.6634$ .

This probability is P(X = 1). So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 2) = C_{2,1}.(0.6634)^{1}.(0.3366)^{1} = 0.4466$

0.4466 = 44.66% probability that, in exactly one of the two classes, all 8 students pass.

3 0

2 years ago