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SashulF [63]
4 years ago
9

PLEASE HELP (URGENT)! WILL MARK THE BRAINLIEST!!! PLEASE HELP!!!!!

Mathematics
1 answer:
miv72 [106K]4 years ago
4 0

According to the question the annual percentage rate is 5%, but in the online calculator he put 60%, when he needed to 5%.

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What are the steps to solving 5(-2)(4)^2 + 2(4) + 7(-2) ?
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5(-2)(4)^2 + 2(4) + 7(-2)
5(-2)(16) + 2(4) + 7(-2)
-160 + 2(4) + 7(-2)
-160 + 8 + 7(-2)
-160 + 8 + -14
-160 + 8 - 14
-166

The answer is: -166.
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3 years ago
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Circumference and area of a circular piece of glass
Vadim26 [7]

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8 0
3 years ago
Joe's annual income has been increasing in the same dollar amount. The first year his income was $15,200, and the 4th year his i
lidiya [134]

Answer:

Therefore 6th year his income was $19,700.

Step-by-step explanation:

Given, Joe's annual income has been increasing in some dollar amount . The first year his income was $15,200 and 4th  year his income was $17,900.

A=$17900, P= $15,200 and n = 3 year

A= P(1+\frac{r}{100} )^n

\Leftrightarrow 17900=15200(1+\frac{r}{100})^3

\Leftrightarrow (1+\frac{r}{100})^3=\frac{17900}{15200}

\Leftrightarrow (1+\frac{r}{100})=(\frac{17900}{15200})^{\frac{1}{3} }

\Leftrightarrow \frac{r}{100}=(\frac{17900}{15200})^{\frac{1}{3} }-1

\Leftrightarrow r=5.60

Let  t^{th} year Joe's income was $19,700.

\therefore 19700=15,200(1+\frac{5.60}{100} )^{t-1}

\Leftrightarrow 1.296= (1+0.056)^{t-1}

\Leftrightarrow 1.296= (1.056)^{t-1}

\Leftrightarrow  log(1.296)= (t-1)log(1.056)

\Leftrightarrow  \frac{log(1.296)}{log(1.056)}= (t-1)

\Leftrightarrow t-1= 4.75

\Leftrightarrow t= 4.75+1

\Leftrightarrow t = 5.75 ≈6

Therefore 6th year his income was $19,700.

8 0
3 years ago
11
aalyn [17]

Answer:

rational, integer

Step-by-step explanation:

5 0
4 years ago
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