HELP!!! I dont understand this!!! (BRAINLIEST)

Rom4ik [11]

Right angles are usually always 90 degrees, then if you are looking at right triangles, you have 45,45,90 degree triangles and 30,60,90 triangles

5 0

3 years ago

Dawn enjoys exercising on the hiking trail by her house. She ran 2/5 of

Artist 52 [7]

Answer:

11/15 of the trail

Step-by-step explanation:

Step one:

given data

She ran 2/5 of the trail on Monday

Then ran a different 1/3 of the trail on Tuesday

Required

The total distance covered for Monday and Tuesday

Step two:

Total= 2/5+1/3

lcm= 15

Total= 6+5/15

Total= 11/15

3 0

3 years ago

A. Complete the chart based on the initial conditions:

Nata [24]

Answer:

a.

$Month\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ Pop(whole \ ant)\\month1 => x_1=80\times0.94^1=1128\\month2=>x_2=1200\times0.94^2=1060\\month3=>x_3=1200\times0.94^3=996\\month4=>x_4=1200\times0.94^4=936$

b.

$week Number\ \ \ \ \ \ \ \ \ \ \ \ \ \ Mass(g)\\week1 => x_1=80\times1.1^1=88g\\week2=>x_2=80\times1.1^2=96.8g\\week3=>x_3=80\times1.1^3=106.48g\\week4=>x_4=80\times1.1^4=117.128g$

Step-by-step explanation:

a. From the information provided, we can deduce that the population death's follows a Geometric sequence in the form $(a,ar,ar^2,ar^3...)$ where $a-first \ term$ and $r-common \ ratio$

#Since the population is reducing, $r$ can is obtained as $r=1-r=0.94$

#The $n^t^h$ term is obtained using the formula $x_n=ar^(^n^-^1^)$ , given a=1200

The number of ants alive after every month (in first 4 months)

$Month\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ Pop(whole \ ant)\\month1 => x_1=80\times0.94^1=1128\\month2=>x_2=1200\times0.94^2=1060\\month3=>x_3=1200\times0.94^3=996\\month4=>x_4=1200\times0.94^4=936$

The ant's alive after 4 months is obtained as the value of $x_5$

$x_n=ar^(^n^-^1^)\\1-x_5=1-1200\times 0.94^4=936.89\\\approx 936$

Hence, 936 ants are alive after 4 months.

b. As with the above question, the kitten population follows a geometric sequence: $(a,ar,ar^2,ar^3...)$ .

#Since it's a growing population , the common ration is the sum of 100% + the growth rate,

$r=1.1$ and $a=80$ and $x_n=ar^(^n^-^1^)$

The population after 4weeks will be:

$week Number\ \ \ \ \ \ \ \ \ \ \ \ \ \ Mass(g)\\week1 => x_1=80\times1.1^1=88g\\week2=>x_2=80\times1.1^2=96.8g\\week3=>x_3=80\times1.1^3=106.48g\\week4=>x_4=80\times1.1^4=117.128g$

8 0

4 years ago

Marissa borrowed $5,500 from the bank and paid $1,100 in interest. To identify the interest rate, she needed to find what percen

blagie [28]

Answer:

0.2 which is 20%

Step-by-step explanation:

divide $5,500 from $1,100. Which equals 0.2 or 20%.

I hope this helped if not im am so sorry

4 0

4 years ago

Solve for x: 3x − 5 = 2x + 6. need answer plz :(