I would make both denominators the same, and the lowest one that works is 18. So I'd make 1/9 into 2/18, and 1/6 into 3/18. They already used these times so combine them to make 5/18 then subtract that from the total time they had (18/18) and you would get 13/18 they spent playing music.
Answer:
t = 4 seconds
Step-by-step explanation:
The height of the projectile after it is launched is given by the function :

t is time in seconds
We need to find after how many seconds will the projectile land back on the ground. When it land, h(t)=0
So,

The above is a quadratic equation. It can be solved by the formula as follows :

Here, a = -16, b = 32 and c = 128

Neglecting negative value, the projectile will land after 4 seconds.
Step-by-step explanation:
angle 1=180-(90+58)
=180-148
=32
angle1=angle2=32
angle3=180-(108+32)
=180-140
=40°
Answer:
No, is 0.675
Step-by-step explanation:
I am not sure if i understand