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2 years ago

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Geometry is the study of how shapes and space and things that we see . . . a. Change the way we use science b. Affect our though

ts on life c. Differ from how our parents understood math d. Relate to each other e. Make a difference in school

1 answer:

geniusboy [140]2 years ago

5 0

Answer:

a. Change the way we use science

Step-by-step explanation:

Geometry is one of the oldest branch of mathematics. It deals with the shapes and forms and sizes of different objects and the principles of of providing solution to world life problem using these concepts.

It provides scientific solutions to many real life problems. It has many practical utilization in our daily lives. We can provide any solution by using different concepts of science to it.

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The sides of △FGH are FG = 6 x+ 7, GH = 8x - 5, and FH = 10x - 11. If the perimeter of △FGH is 87, list the angles in order from

irga5000 [103]

Answer:

From largest to smallest: FG, FH, GH

Step-by-step explanation:

Given

$FG = 6x + 7$

$GH = 8x - 5$

$FH = 10x - 11$

$Perimeter = 87$

Required

Order the sides in descending order

First, we need to solve for x.

Perimeter of FGH is calculated as thus:

$Perimeter = FG + GH + FH$

Substitute values for FG, GH, FH and Perimeter

$87 = 6x + 7 + 8x - 5 + 10x - 11$

Collect Like Terms

$87 - 7 + 5 + 11= 6x + 8x + 10x$

$96= 24x$

Reorder

$24x = 96$

Divide through by 24

$x = 96/24$

$x = 4$

Substitute 4 for x in FG, GH and FH

$FG = 6x + 7$

$FG = 6 * 4 + 7$

$FG = 24 + 7$

$FG =31$

$GH = 8x - 5$

$GH = 8 * 4 - 5$

$GH = 32 - 5$

$GH = 27$

$FH = 10x - 11$

$FH = 10*4 - 11$

$FH = 40 - 11$

$FH = 29$

In order of arrangement in descending order, we have:

$FG =31$ $FH = 29$ $GH = 27$

4 0

2 years ago

The sea ice area around the North Pole fluctuates between about 6 million square kilometers in September to 14 million square ki

Aleksandr [31]

Answer:

there are approximately 5.035 months when there is less than 9 million square meters of sea ice around the North Pole in a year.

Step-by-step explanation:

Given the data in the question;

Let S(t) represent the amount sea ice around the North Pole in millions of square meters at a given time t,

t is the number of months since January.

Now, we use a cosine curve to model this scenario

Vertical shift will be;

D = ( 6 + 14 ) / 2 = 20 / 2

D = 10

Next is the Amplitude;

|A| = ( 6 - 14 ) / 2

|A| = 4

Now, the horizontal stretch factor will be;

B = 2π / 12

B = π/6

Hence;

S(t) = 4cos( π/6 × t ) + 10 ----------- let this be equation 1

Now we find when there will be less than 9 million square meters of sea ice;

S(t) = 9

so we have

9 = 4cos( π/6 × (t-2) ) + 10

9 - 10 = 4cos( π/6 × (t-2) )

-1 = 4cos( π/6 × (t-2) )

-1/4 = cos( π/6 × (t-2) )

so we have;

cos⁻¹( -1/4 ) = π/6 × (t₁-2) -------- let this be equation 2

2π - cos⁻¹( -1/4 ) = π/6 × (t₂-2) -------- let this be equation 3

so we solve equation 2 and 3

we have'

t₁ - t₂ = 6/π × ( 2π - cos⁻¹( -1/4 ) - cos⁻¹( -1/4 ) )

t₁ - t₂ = 6/π × ( 2π - 2cos⁻¹( -1/4 )

t₁ - t₂ = 6/π × ( π - cos⁻¹( -1/4 )

t₁ - t₂ = 6/π × ( π - 104.4775 )

t₁ - t₂ = 6/π × ( π - 104.4775 )

t₁ - t₂ = 5.035

therefore, there are approximately 5.035 months when there is less than 9 million square meters of sea ice around the North Pole in a year.

6 0

2 years ago

Please help with this question!! I need serious help!!

asambeis [7]

Answer:

<h2>The circumference is multipled by 4.</h2>

Step-by-step explanation:

The formula of an area of a circle"

$A=\pi r^2$

The formula of a circumference of a circle:

$C=2\pi r$

The area multipled by 16:

$16A=16\pi r^2\\\\16A=\pi(4^2r^2)\\\\16A=\pi(4r)^2$

The radius has increased fourfold, therefore:

$C'=2\pi(4r)=4(2\pi r)=4C$

The circumference is multipled by 4.

You can calculate the area and check the circumference:

$r=11.6\ in\\\\A=\pi(11.6)^2=132.56\pi\\\\16A=(16)(134.56\pi)=2152.96\pi\ in^2$

Calculate the radius:

$\pi r^2=2152.96\pi$ <em>divide both sides by π</em>

$r^2=2152.96\to r=\sqrt{2152.96}\\\\r=46.4\ in$

Calculate the circumference of both circles:

$r=11.6\ in\\\\C=2\pi(11.6)=23.2\pi\ in$

$r=46.4\ in\\\\C'=2\pi(46.4)=92.8\pi\ in$

$\dfrac{C'}{C}=\dfrac{92.8\pi}{23.2\pi}=4\to C'=4C$

5 0

2 years ago

Match each point label on the box it to its description.

Ahat [919]

A is the minimum value
B is the first quartile
The point with the line through it (next to C) is the median.
The point to the outside of the box is the third quartile.
D is the maximum value.

Hope this helped.

4 0

2 years ago

Properties of isosceles triangle

Degger [83]

Answer:

Had two congruent sides

Has congruent base angles

8 0

2 years ago