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Alchen [17]
2 years ago
13

I need help with these.

Mathematics
1 answer:
diamong [38]2 years ago
6 0
3848 383848 999393 2938
You might be interested in
For any integer x,x2-x will always produce an even value
Levart [38]

Consider expression x^2-x. First, you can factor it:

x^2-x=x(x-1).

Since x is integer number, then you can see that x-1 is previous integer number (x-1 is 1 unit smaller than x).

Therefore, x-1 and x are two consecutive integers. When you have two consecutive integers, one of them is always even and one is always odd. Multiplying even integer number by odd integer number you always get even integer number.

Thus, x^2-x is always even.

8 0
3 years ago
Which is the correct answer
denpristay [2]

Answer:

44 2/4

Step-by-step explanation:

178/4= 44.5

44 2/4 =

44 x 4 = 176

176 + 2 = 178

hope this helps and if it is wrong i am sorry

4 0
2 years ago
Using the quadratic formula to solve 4x2 – 3x + 9 = 2x + 1, what are the values of x?
yaroslaw [1]

Answer:

The value of x is:

x=\dfrac{5\pm \sqrt{103}i}{8}

Step-by-step explanation:

we have to use the quadratic formula to solve for x.

The equation is given as:

4x^2-3x+9=2x+1

which could also be written as:

4x^2-3x+9-2x-1=0\\\\4x^2-3x-2x+9-1=0\\\\\\4x^2-5x+8=0

The quadratic formula for the quadratic equation of the type:

ax^2+bx+c=0 is given as:

x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}

Here we have:

a=4, b=-5 and c=8.

Hence, by the quadratic formula we have:

x=\dfrac{-(-5)\pm \sqrt{(-5)^2-4\times 8\times 4}}{2\times 4}\\\\x=\dfrac{5\pm \sqrt{25-128}}{8}\\\\\\x=\dfrac{5\pm \sqrt{103}i}{8}

Hence, the value of x is:

x=\dfrac{5\pm \sqrt{103}i}{8}

8 0
3 years ago
Read 2 more answers
How many solutions does the following equation have? -3z + 9 -2z = -12 - 5z
asambeis [7]
This has no solutions
4 0
3 years ago
If The diameter of a circle is 14 yards.what is the circles circumference
amm1812

Answer:

14π yards^2, or 43.98^2 yards rounded to 2dp

Step-by-step explanation:

circumference = diameter x π

6 0
3 years ago
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