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Alchen [17]
2 years ago
13

I need help with these.

Mathematics
1 answer:
diamong [38]2 years ago
6 0
3848 383848 999393 2938
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A chemist mixes milliliters of a solution that is acid with milliliters of a solution that is acid.
Stells [14]
Where’s the question??
4 0
3 years ago
3(5 p - 1 p ) - 4 ( 3 p -7) when p = 4​
Lilit [14]

Answer:

=28

Step-by-step explanation:

3(5 p - 1 p ) - 4 ( 3 p -7) when p = 4​

3 (20-4) -4 ( 12 - 7)

60 - 12 -48 +28

= 28

5 0
2 years ago
Read 2 more answers
Solve each equation.<br><br> Captionless Image<br> a<br> b<br> c<br> d
Finger [1]

Answer:

d) n = -5 and n = -3

Step-by-step explanation:

n²+8n+15=0

Step 1: Factor left side of equation.

(n+3)(n+5)=0

Step 2: Set factors equal to 0.

n+3=0 or n+5=0

n=−3 or n=−5

3 0
3 years ago
7x+2y=57x+2y=5 how do you do it
timofeeve [1]

The value of x=\frac{26}{3}, \ y=\frac{-11}{6}.

Solution:

Given equations:

7x + 2y = 57 ---------- (1)

x + 2y = 5 ---------- (2)

Subtract 2y from both sides of the equation (2).

x = 5 – 2y ---------- (3)

Substitute equation (3) in equation (1).

7(5 – 2y) + 2y = 57

35 – 14y + 2y = 57

35 – 12y = 57

Subtract 35 from both sides of the equation.

–12y = 22

Divide by 12 on both sides.

$y=\frac{-11}{6}

Substitute y value in equation (3).

x=5-2(\frac{-11}{6} )

x=5+\frac{11}{3}

$x=\frac{26}{3}

Hence the value of x=\frac{26}{3}, \ y=\frac{-11}{6}.

4 0
3 years ago
which choices are equivalent to the expression below. check all apply sqrt 2 x sqrt 5 x sqrt 10A. 10B. 15C. 10 over sqrt 10D. 10
VMariaS [17]
\begin{gathered} \sqrt[]{2}\cdot\sqrt[]{5}\cdot\sqrt[]{10} \\ \sqrt[]{2}\cdot\sqrt[]{5}\cdot\sqrt[]{2\cdot5} \\ \sqrt[]{2^2}\cdot\sqrt[]{5^2} \\ 2\cdot5=10 \end{gathered}

The first is to decouple the 10 into 2 * 5 and extract the values within the root. The other is to enter all the values to the same root and calculate in general

\begin{gathered} \sqrt[]{2}\cdot\sqrt[]{5}\cdot\sqrt[]{10}=\sqrt[]{2\cdot5\cdot10} \\ \sqrt[]{100}=10 \end{gathered}

8 0
1 year ago
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