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2 years ago

I need help with these.

Mathematics

1 answer:

diamong [38]2 years ago

6 0

3848 383848 999393 2938

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A chemist mixes milliliters of a solution that is acid with milliliters of a solution that is acid.

Stells [14]

Where’s the question??

4 0

3 years ago

3(5 p - 1 p ) - 4 ( 3 p -7) when p = 4

Lilit [14]

Answer:

=28

Step-by-step explanation:

3(5 p - 1 p ) - 4 ( 3 p -7) when p = 4

3 (20-4) -4 ( 12 - 7)

60 - 12 -48 +28

= 28

5 0

2 years ago

Read 2 more answers

Solve each equation. Captionless Image a b c d

Finger [1]

Answer:

d) n = -5 and n = -3

Step-by-step explanation:

n²+8n+15=0

Step 1: Factor left side of equation.

(n+3)(n+5)=0

Step 2: Set factors equal to 0.

n+3=0 or n+5=0

n=−3 or n=−5

3 0

3 years ago

7x+2y=57x+2y=5 how do you do it

timofeeve [1]

The value of $x=\frac{26}{3}, \ y=\frac{-11}{6}$ .

Solution:

Given equations:

7x + 2y = 57 ---------- (1)

x + 2y = 5 ---------- (2)

Subtract 2y from both sides of the equation (2).

x = 5 – 2y ---------- (3)

Substitute equation (3) in equation (1).

7(5 – 2y) + 2y = 57

35 – 14y + 2y = 57

35 – 12y = 57

Subtract 35 from both sides of the equation.

–12y = 22

Divide by 12 on both sides.

$$y=\frac{-11}{6}$

Substitute y value in equation (3).

$x=5-2(\frac{-11}{6} )$

$x=5+\frac{11}{3}$

$$x=\frac{26}{3}$

Hence the value of $x=\frac{26}{3}, \ y=\frac{-11}{6}$ .

4 0

3 years ago

which choices are equivalent to the expression below. check all apply sqrt 2 x sqrt 5 x sqrt 10A. 10B. 15C. 10 over sqrt 10D. 10

VMariaS [17]

$\begin{gathered} \sqrt[]{2}\cdot\sqrt[]{5}\cdot\sqrt[]{10} \\ \sqrt[]{2}\cdot\sqrt[]{5}\cdot\sqrt[]{2\cdot5} \\ \sqrt[]{2^2}\cdot\sqrt[]{5^2} \\ 2\cdot5=10 \end{gathered}$

The first is to decouple the 10 into 2 * 5 and extract the values within the root. The other is to enter all the values to the same root and calculate in general

$\begin{gathered} \sqrt[]{2}\cdot\sqrt[]{5}\cdot\sqrt[]{10}=\sqrt[]{2\cdot5\cdot10} \\ \sqrt[]{100}=10 \end{gathered}$

8 0

1 year ago