Question

Help me how should i answer this

Answer 1

Answer:

$\frac{3}{10}$

Step-by-step explanation:

The average rate of change of a function over the interval $[a,b]$ is $\frac{f(b)-f(a)}{b-a}$.

Since $[a,b]\rightarrow[0,20]$, then for throw #3:

$\frac{f(b)-f(a)}{b-a}\\\\\frac{f(20)-f(0)}{20-0}\\\\\frac{12-6}{20}\\ \\\frac{6}{20}\\ \\\frac{3}{10}$

This means that the average rate of change over the interval [0,20] for Throw #3 is $\frac{3}{10}$.