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MatroZZZ [7]
3 years ago
5

Find the volume. 10 2/3 in , 3 in , and 6 3/8

Mathematics
1 answer:
aleksandr82 [10.1K]3 years ago
8 0

Volume of the box is 204 in³

<u>Step-by-step explanation:</u>

Step 1:

Volume of the box = length × width × height

Length = 10 2/3 = 32/3 in,

width = 3 in and height = 6 3/8 = 51/8 in

⇒ Volume = 32/3 × 3 × 51/8 = 4 × 51 = 204 in³

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Mr. Johnson currently has a square garden. He wants to redesign his garden and make it into a rectangle with a length that is 5
AlekseyPX

Answer:

Width of the rectangle = 10 feet

Length of the rectangle = 25 feet

Step-by-step explanation:

Perimeter of a rectangle = 2(length + width)

Let

Width of the rectangle = x feet

Length of the rectangle = 3x - 5 feet

Perimeter of the rectangle = 70 feet

Perimeter of a rectangle = 2(length + width)

70 = 2{x + (3x - 5)}

70 = 2{x + 3x - 5}

70 = 2(4x - 5)

70 = 8x - 10

70 + 10 = 8x

80 = 8x

Divide both sides by 8

x = 80 / 8

= 10

Width of the rectangle = 10 feet

Length of the rectangle = 3(10) - 5

= 30 - 5

= 25 feet

6 0
2 years ago
Help plzzzzzzzzzzzzzzz
Tasya [4]

Answer:

3.843

Step-by-step explanation:

(3x1)= 1

(8x1/10= 0.8

(4x1/100)=0.04

(3x1/1000)=0.003

Then, add together to get 3.843.

5 0
3 years ago
Please help with this question ​
leonid [27]

We know that \sin(45)=\cos(45) and this is the only point when sin and cos are equal lengths. Because both \sin(45),\cos(45)=\dfrac{\sqrt{2}}{2}

Now if the sin of 30° is a half that would mean that cos of 60° is also a half.

Hope this helps.

<u>r3t40</u>

5 0
3 years ago
What is bigger 9/10 or 7/8
Nataliya [291]
You start by cross multiplying:
9 x 8 = 72
This is considered the fraction on the left's value.
You do the same for the other side:
10 x 7 = 70
This is considered the value of the fraction 7/8
72 has a greater value than 70.

Therefore, 9/10 is larger.
4 0
3 years ago
Read 2 more answers
A tank with a capacity of 1000 L is full of a mixture of water and chlorine with a concentration of 0.02 g of chlorine per liter
faltersainse [42]

At the start, the tank contains

(0.02 g/L) * (1000 L) = 20 g

of chlorine. Let <em>c</em> (<em>t</em> ) denote the amount of chlorine (in grams) in the tank at time <em>t </em>.

Pure water is pumped into the tank, so no chlorine is flowing into it, but is flowing out at a rate of

(<em>c</em> (<em>t</em> )/(1000 + (10 - 25)<em>t</em> ) g/L) * (25 L/s) = 5<em>c</em> (<em>t</em> ) /(200 - 3<em>t</em> ) g/s

In case it's unclear why this is the case:

The amount of liquid in the tank at the start is 1000 L. If water is pumped in at a rate of 10 L/s, then after <em>t</em> s there will be (1000 + 10<em>t</em> ) L of liquid in the tank. But we're also removing 25 L from the tank per second, so there is a net "gain" of 10 - 25 = -15 L of liquid each second. So the volume of liquid in the tank at time <em>t</em> is (1000 - 15<em>t </em>) L. Then the concentration of chlorine per unit volume is <em>c</em> (<em>t</em> ) divided by this volume.

So the amount of chlorine in the tank changes according to

\dfrac{\mathrm dc(t)}{\mathrm dt}=-\dfrac{5c(t)}{200-3t}

which is a linear equation. Move the non-derivative term to the left, then multiply both sides by the integrating factor 1/(200 - 5<em>t</em> )^(5/3), then integrate both sides to solve for <em>c</em> (<em>t</em> ):

\dfrac{\mathrm dc(t)}{\mathrm dt}+\dfrac{5c(t)}{200-3t}=0

\dfrac1{(200-3t)^{5/3}}\dfrac{\mathrm dc(t)}{\mathrm dt}+\dfrac{5c(t)}{(200-3t)^{8/3}}=0

\dfrac{\mathrm d}{\mathrm dt}\left[\dfrac{c(t)}{(200-3t)^{5/3}}\right]=0

\dfrac{c(t)}{(200-3t)^{5/3}}=C

c(t)=C(200-3t)^{5/3}

There are 20 g of chlorine at the start, so <em>c</em> (0) = 20. Use this to solve for <em>C</em> :

20=C(200)^{5/3}\implies C=\dfrac1{200\cdot5^{1/3}}

\implies\boxed{c(t)=\dfrac1{200}\sqrt[3]{\dfrac{(200-3t)^5}5}}

7 0
3 years ago
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