The population Pa of insect A after t years is given by the equation
Pa = 1.3(1-0.038)^t
while the population Pb of insect B after t years is
Pb = 2.1(1-0.046)^t
We equate the above expressions to find the number of years t it will take the two populations to be equal:
Pa = Pb
1.3(1-0.038)^t = 2.1(1-0.046)^t
1.3(0.962)^t = 2.1(0.954)^t
These are the equations that can be used to determine how long it will be before the populations of the two species are equal.
We can now solve for t:
(0.962)^t / (0.954)^t = 2.1/1.3
(0.962/0.954)^t = 2.1/1.3
After taking the log of both sides of our equation, number of years t is
t = log (2.1/1.3) / log (0.962/0.954)
t = 57 years
Therefore, it will take 57 years for the population of insect A to equal the population of insect B.
Anijahgreen, I need to take some tiome to do this, ill have answer in aminute.
This would be 85 use the percent in division
235.24 + 45.58 = 280.82
280.82/2 = 140.41
each check was for $140.41
It looks like the differential equation is
Multiply both sides by 1/(<em>x</em> + 1) :
The left side is now a derivative of a product,
Integrate both sides with respect to <em>x</em> :
Solve for <em>y</em> :
