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3 years ago

How many solutions are there to the equation below?

Mathematics

2 answers:

kotegsom [21]3 years ago

7 0

Answer:

It would be 0

Step-by-step explanation:

because its -7x+20=13-7x which in the end would 20=13

elena55 [62]3 years ago

5 0

Answer:

A) 0 (no solutions)

Step-by-step explanation:

Solve the equation:

3x - 10(x+2) = 13 - 7x

3x - 10x -20 = 13 - 7x

-7x - 20 = 13 - 7x

-20 = 13

Since both sides are clearly not equal to each other, no solution can satisfy both sides to be equal to each other. So A is correct.

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PLEASE HELP!!

VladimirAG [237]

Answer:

Sphere Volume = (4/3) * PI * radius^3

radius = cube root (Sphere Volume) / (4/3)*PI

radius = cube root (5,600) / (4/3)*PI

radius = 11.016 cm

radius = 11 cm (rounded)

Answer is B

Step-by-step explanation:

4 0

3 years ago

2 What is the range of the numbers 11, 24, 37, 44, and 62? 24.44 11372 A6 A А 62 B. 52 С 51 D 49

inessss [21]

Answer:

range = 51

Step-by-step explanation:

Range = biggest - smallest

62 - 11 = 51

5 0

3 years ago

| 3. Find the Area of the triangle. 8.6 yd 10.9 yd

Nitella [24]

Given:

The base of the triangle = 8.6 yd

The height of the triangle = 10.9 yd

To find the area of the triangle.

Formula

The area of a triangle with b as base and h as height is

$A=\frac{1}{2}bh$

Now,

Taking, b= 8.6 and h = 10.9 we get,

$A=\frac{1}{2}(8.6)(10.9)$ sq yd

or, $A= 46.87$ sq yd

Hence,

The area of the given triangle is 46.87 sq yd.

7 0

3 years ago

Read 2 more answers

X^2-12x+36=0

kari74 [83]

This expression is a perfect square trinomial. It has two answers but they don't have to be different. In this case it has to be the same - because it is a perfect square trinomial.

6 0

3 years ago

Read 2 more answers

Find the maximum and minimum values of the function f(x,y)=2x2+3y2−4x−5 on the domain x2+y2≤100. The maximum value of f(x,y) is:

ryzh [129]

First find the critical points of f :

$f(x,y)=2x^2+3y^2-4x-5=2(x-1)^2+3y^2-7$

$\dfrac{\partial f}{\partial x}=2(x-1)=0\implies x=1$

$\dfrac{\partial f}{\partial y}=6y=0\implies y=0$

so the point (1, 0) is the only critical point, at which we have

$f(1,0)=-7$

Next check for critical points along the boundary, which can be found by converting to polar coordinates:

$f(x,y)=f(10\cos t,10\sin t)=g(t)=295-40\cos t-100\cos^2t$

Find the critical points of g :

$\dfrac{\mathrm dg}{\mathrm dt}=40\sin t+200\sin t\cos t=40\sin t(1+5\cos t)=0$

$\implies\sin t=0\text{ OR }1+5\cos t=0$

$\implies t=n\pi\text{ OR }t=\cos^{-1}\left(-\dfrac15\right)+2n\pi\text{ OR }t=-\cos^{-1}\left(-\dfrac15\right)+2n\pi$

where n is any integer. We get 4 critical points in the interval [0, 2π) at

$t=0\implies f(10,0)=155$

$t=\cos^{-1}\left(-\dfrac15\right)\implies f(-2,4\sqrt6)=299$

$t=\pi\implies f(-10,0)=235$

$t=2\pi-\cos^{-1}\left(-\dfrac15\right)\implies f(-2,-4\sqrt6)=299$

So f has a minimum of -7 and a maximum of 299.

4 0

3 years ago