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jolli1 [7]
3 years ago
11

How to do the inequality 6/5x>-3/2

Mathematics
1 answer:
DIA [1.3K]3 years ago
4 0

Answer:

x > - \frac{5}{4}

Step-by-step explanation:

Given

\frac{6}{5} x > - \frac{3}{2}

Multiply both sides by 10 to clear the fractions

12x > - 15 ( divide both sides by 12 )

x > - \frac{15}{12}, that is

x > - \frac{5}{4}

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24 + 0.44x = 19 + 1.69x
lys-0071 [83]

Answer:

if it is find the value of x her it is

24 + 0.44x = 19 + 1.69x \\ collect \: like \: terms \\ 24 - 19 = 1.69x - 0.44x \\ 5 = 1.25x \\ divide \: both \: side \: by \: 1.25 \\  \frac{5}{1.25}  =  \frac{1.25x}{1.25}  \\ 4 = x \\ x = 4

6 0
3 years ago
Help me with this pls pls pls
nikklg [1K]
3 1/2
Becase if you turn them both in to inporper fractions then you can do other sh1t to find it out
5 0
4 years ago
The length of a rectangle is twice it’s width if the perimeter of the rectangle is 60 yards find its length and width
grandymaker [24]
Length =20
width =10

6 0
4 years ago
Which of the following graphs is a polynomial function with x-intercepts of (-3,0)(-1,0), and (2,0)?​
Helen [10]
The intercepts of the third degree polynomial corresponds to the zeros of the equation
y = d*(x-a)*(x-b)(x-c)
Where a, b and c are the roots of the polynomial and d an adjustment coefficient.
y = d*(x+2)*(x)*(x-3)
Lets assume d = 1, and we get
y = (x+2)*(x)*(x-3) = x^3 - x^2 - 6x
We graph the equation in the attached file.

7 0
3 years ago
Read 2 more answers
If f(x) = x^2-1 which of the following ordered pairs would be on the graph of f(x)
Alex Ar [27]

These following ordered pairs are on the graph:

  • (0,1)
  • (5, 24)
  • (-2,3)

-------------------------------

An ordered pair (x, f(x)) will be on the graph if replacing them into the equation, we get an equivalence.

-------------------------------

The equation is:

f(x) = x^2 - 1

-------------------------------

(0,1)

Here, we test x = 0, f(x) = 1

Replacing into the equation:

1 = 0^2 - 1

1 = -1

False, so not on the graph.

-------------------------------

(0,1)

Here, we test x = 1, f(x) = 0

Replacing into the equation:

0 = 1^2 - 1

0 = 0

True, so on the graph.

-------------------------------

(3,5)

Here, we test x = 3, f(x) = 5

Replacing into the equation:

5 = 3^2 - 1

5 = 8

False, so not on the graph.

-------------------------------

(5,24)

Here, we test x = 5, f(x) = 24

Replacing into the equation:

24 = 5^2 - 1

24 = 24

True, so on the graph.

-------------------------------

(-2,3)

Here, we test x = -2, f(x) = 3

Replacing into the equation:

3 = (-2)^2 - 1

3 = 3

True, so on the graph.

-------------------------------

(-4,-17)

Here, we test x = -4, f(x) = -17

Replacing into the equation:

-17 = (-4)^2 - 1

-17 = 15

False, so not on the graph.

A similar question is given at brainly.com/question/2102317

6 0
3 years ago
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