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2 years ago

Not sure how I would solve this

Mathematics

1 answer:

Elden [556K]2 years ago

4 0

Answer:

7/6

Step-by-step explanation:

m = (y2-y1)/(x2-x1)

Using the given points

m = (-2 - -9)/(2 -8)

= (-2+9) / (-6)

= 7/6

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The histogram to the right represents the weights (in pounds) of members of a certain high-school math team. How many team mem

____ [38]

Answer:

Total member = a+b+c+d+e+f+g=5+4+2+0+5+0+4=20 member

Step-by-step explanation:

Let suppose the attached histogram

a) Total members whose weight 110 = 5

b) Total members whose weight 120 = 4

c) Total members whose weight 130 = 2

d) Total members whose weight 140 = 0

e) Total members whose weight 150 = 5

f) Total members whose weight 160 = 0

g) Total members whose weight 170 = 4

Total member = a+b+c+d+e+f+g=5+4+2+0+5+0+4=20 member

A histogram is a statistical graphical representation of data with the help of bars with different heights.

6 0

2 years ago

Please answer these questions and have the work shown:

ahrayia [7]

Answer:

number one 50 I think and 3 is 75 not positive but I hope it helps

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

Can i have help with these questions

adell [148]

Answer:

(-3, 5), (-1, -1), (5, -3)

Step-by-step explanation:

Each pair of vertices can be one of the diagonals. Then the missing point will be found at the coordinates that are the sum of those, less the coordinates of the third point.

Given points are ...

A(-2, 2), B(1, 1), C(2, -2)

For AB a diagonal, D1 is ...

A+B-C = (-2+1-2, 2+1-(-2)) = (-3, 5)

For AC a diagonal, D2 is ...

A+C-B = (-2+2-1, 2-2-1) = (-1, -1)

For BC a diagonal, D3 is ...

B+C-A = (1+2-(-2), 1-2-2) = (5, -3)

_____

For a lot of parallelogram problems I find it easiest to work with the fact that the diagonals bisect each other. This means they both have the same midpoint, so for quadrilateral ABCD, we have (A+C)/2 = (B+D)/2. Multiplying this by 2 gives the equation we used above, A+C = B+D, so D=A+C-B. Remember, in ABCD, AC and BD are the diagonals.