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Arturiano [62]
4 years ago
8

Andres dog weighs 18 pounds. The vet says the breed of his dog typically weighs about 8 kg. How many kg is andres dog above the

typical weight? (One kg is about 2.2 lbs.)
Mathematics
1 answer:
Liono4ka [1.6K]4 years ago
7 0
18-8=10

10*2.2=22

his dog is 22 lbs above the typical weight   
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Plz help ill give you brainlist to yuo
Wittaler [7]
The coefficient is a number that is placed in front of the variable for which It is being multiplied to. In this case it would be 5.

Constants are values that can be thought of as the opposite of coefficients in that they do not have any other variables or letters and thus they include only a number.

Their value does not change.
8 0
3 years ago
Two number cubes are rolled for two separate events: 
MatroZZZ [7]

Let us first make the sample space for the event A. The Sample Space will be:

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)

(4,1) (4,2) (4,3) (4,4) (4,5)

(5,1) (5,2) (5,3) (5,4)

(6,1) (6,2) (6,3)

As can be clearly seen the Sample Space for the event A has 30 elements in it.

Now, it is given in the question that the event A has already occurred and we need to find the probability of the event B occurring <u><em>given that the event A has already occurred.</em></u>

Now, as we can see, from the sample space, only 11 events out of the 30 are the events of interest to us. This is shown in bold below:

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)

(4,1) (4,2) (4,3) (4,4) (4,5)

(5,1) (5,2) (5,3) (5,4)

(6,1) (6,2) (6,3)

Thus, the probability that the event B occurs given that the event A has already occurred is:

P(B|A)=\frac{11}{30}\approx0.367

In percentage the required probability is 36.7% approximately.

3 0
3 years ago
Find the other endpoint of the line segment with the given endpoint and midpoint. Endpoint: (9,8) Midpoint (0,9)​
shepuryov [24]

Answer:

(-9, 10)

Step-by-step explanation:

The location of the midpoint of a line with endpoint at (x_1,y_1) and (x_2,y_2) is given as (x, y). The location of x and y are:

x = \frac{x_1+x_2}{2},y=\frac{y_1+y_2}{2}

Given the endpoint (9,8) and Midpoint (0,9), the location of the other endpoint can be gotten from:

0=\frac{9+x_2}{2}\\ \\9+x_2=0\\\\x_2=-9\\\\Also,9=\frac{8+y_2}{2}\\ \\8+y_2=18\\\\y_2=18-8\\\\y_2=10

Hence the endpoint is at (x2, y2) which is at (-9, 10)

5 0
4 years ago
Solve 7x - 9 = 28 + 4(x - 1).<br><br> A X = -11<br> B x = 11<br> C X = 3<br> D x=-3
frozen [14]
Answer is A. X= 11
Have a good day
3 0
3 years ago
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Which of the following ordered pairs could be placed in the table and still have the relation qualify as a linear function?
IrinaVladis [17]
(2, 13) is the answer
3 0
3 years ago
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