The slope of the line that is perpendicular to 6x + 2y = -32 is: 1/3.
<h3>What is the Slope of Perpendicular Lines?</h3>
The slope of two lines that are perpendicular to each other will always have a product that is equal to -1, which means that their slopes are negative reciprocals to each other.
Rewrite 6x + 2y = -32 in slope-intercept form:
2y = -6x - 32
2y/2 = -6x/2 - 32/2
y = -3x - 16
The slope is -3. Negative reciprocal of -3 is 1/3.
Therefore, the slope of the perpendicular line would be: 1/3.
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Answer:
x = 7°
<GDH = 112°
<FDH = 192°
<FDE = 135°
Step-by-step explanation:
If DE bisects <GDH this means that <GDE = <EDH
Given <GDE = (8x+1)° and <EDH = (6x+15)° then;
8x+1 = 6x+15
8x-6x = 15-1
2x = 14
x = 7°
Since <GDH = <GDE + <EDH
<GDH = 8x-1+6x+15
<GDH = 14x+14
<GDH = 14(7)+14
<GDH = 98+14
<GDH = 112°
For <FDH,
Note that sum of angle on a straight line is 180°
<FDH = <FDG + <GDE + <EDH
<FDH = <FDG + <GDH
<FDG = 180-(43+8x+1)
<FDG = 180-44-8x = 136-8x
<FDH = 136-8x+112
<FDH = 248-8x
<FDH = 248-8(7)
<FDH = 248-56
<FDH = 192°
For <FDE;
<FDE = <FDG + <GDE
<FDE = 136-8x+8x-1
<FDE = 135°
Answer: the diameter of the circle is 226 cm
Step-by-step explanation:
The formula for determining the length of an arc is expressed as
Length of arc = θ/360 × 2πr
Where
θ represents the central angle.
r represents the radius of the circle.
π is a constant whose value is 3.14
From the information given,
Length of arc = 88π
θ = 140 degrees
Therefore,
88π = 140/360 × 2 × π × r
88π = 140/360 × 2 × π × r
Dividing both sides of the equation by π, it becomes
88 = 140/360 × 2r
88 × 360 = 140 × 2r = 280r
280r = 31680
r = 31680/280
r = 113 cm
Diameter = radius × 2
Diameter = 113 × 2 = 226 cm
yes they are and C has no answer in it and can i have branilest
time 2nd 5/5 it become 35/5x-20
2/5x-20+35/5x-20
=37/5x-20
