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3 years ago

What is that answer

Mathematics

1 answer:

masya89 [10]3 years ago

5 0

Umm it's two obviously

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a box in the shapr of s rectangular prism has a length of 3 5/8 inches, a width of 2 1/2 inches and a height of 4 inches. what i

Sergeeva-Olga [200]

Answer:

V = 36 1/4 in.^3

Step-by-step explanation:

V = LWH

L = 3 5/8 in.

W = 2 1/2 in.

H = 4 in.

V = (3 5/8)(2 1/2)(4) in.^3

Change the mixed numerals to fractions.

<em>To change the mixed numeral a b/c to a fraction, do this: </em>

V = (3 * 8 + 5)/8 * (2 * 2 + 1)/2 * 4/1

V = (24 + 5)/8 * (4 + 1)/2 * 4/1

V = 29/8 * 5/2 * 4/1 in.^3

V = 580/16 in.^3

V = 145/4 in.^3

V = 36 1/4 in.^3

4 0

3 years ago

Use matrices to determine the coordinates of the vertices of the rotated figure. Then graph the pre-image and the image of the s

Sidana [21]

Answer:

10-18=x=9

Step-by-step explanation:

5 0

3 years ago

Mary states, If the diagonals of a parallelogram are congruent, then the parallelogram is a rectangle. Decide if her statement i

Mila [183]

The answer for apex would be true.

8 0

3 years ago

Read 2 more answers

What degree of rotation is represented on this matrix

Korvikt [17]

Answer:

Option B is correct

the degree of rotation is, $-90^{\circ}$

Step-by-step explanation:

A rotation matrix is a matrix that is used to perform a rotation in Euclidean space.

To find the degree of rotation using a standard rotation matrix i.e,

$R = \begin{bmatrix}\cos \theta & -\sin \theta \\ \sin \theta & \cos \theta \end{bmatrix}$

Given the matrix: $\begin{bmatrix}0 & 1 \\ -1 & 0\end{bmatrix}$

Now, equate the given matrix with standard matrix we have;

$\begin{bmatrix}\cos \theta & -\sin \theta \\ \sin \theta & \cos \theta \end{bmatrix}$ = $\begin{bmatrix}0 & 1 \\ -1 & 0\end{bmatrix}$

On comparing we get;

$\cos \theta = 0$ and $-\sin \theta =1$

As,we know:

$\cos \theta = \cos(-\theta)$

$\sin(-\theta) = -\sin \theta$

$\cos \theta = \cos(90^{\circ}) = \cos( -90^{\circ})$

we get;

$\theta = -90^{\circ}$

and

$\sin \theta =- \sin (90^{\circ}) = \sin ( -90^{\circ})$

we get;

$\theta = -90^{\circ}$

Therefore, the degree of rotation is, $-90^{\circ}$

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3 years ago

Write the sum as a product simple simplify the product (-2)+(-2)+(-2)+(-2)

iren [92.7K]

(-2)+(-2)+(-2)+(-2)
=-2-2-2-2
= -8

3 0

3 years ago