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prohojiy [21]
3 years ago
9

Denzel has 3 2/5 boxes of party favors. One full box contains 15 bags of favors and each bag has 3 favors in it. Which expressio

n could be used to find the total number of items that Denzel had ?

Mathematics
1 answer:
Artist 52 [7]3 years ago
5 0

Boxes = 3_2/5

15 = total number of bags of favors

Each bag has 3 items inside

3 × 15 = 45

Total number of items = number of boxes plus (15 × 3).

So, choice A is the answer.

You might be interested in
(b)The graph of y = g(x) is shown. Draw the graph of g(2x). Will award 100 Brainly points
ivanzaharov [21]

Using the stated transformation, the graph of g(2x) is given at the end of the answer.

<h3>Horizontal stretch and compression</h3>

An horizontal stretch or an horizontal compression happens when a constant is multiplied at the domain of the function, as follows:

g(x) = f(ax).

The definition of stretch or compression depends on the value of the constant a, as follows:

  • If a > 1, it is a compression by a factor of 1/a.
  • If a < 1, it is a stretch by a factor of 1/a.

In this problem, the rule is:

f(x) = g(2x).

Meaning that f(x) is an horizontal compression by a factor of 1/2 of g(x), and then the vertices are given as follows:

  • (0,0).
  • (1,-4).
  • (2,-2).

That is, in each vertex, the x-coordinate was divided by 2, and thus the graph with these vertices is given at the end of the answer.

More can be learned about transformations at brainly.com/question/28725644
#SPJ1

8 0
1 year ago
A = 1011 + 337 + 337/2 +1011/10 + 337/5 + ... + 1/2021
egoroff_w [7]

The sum of the given series can be found by simplification of the number

of terms in the series.

  • A is approximately <u>2020.022</u>

Reasons:

The given sequence is presented as follows;

A = 1011 + 337 + 337/2 + 1011/10 + 337/5 + ... + 1/2021

Therefore;

  • \displaystyle A = \mathbf{1011 + \frac{1011}{3} + \frac{1011}{6} + \frac{1011}{10} + \frac{1011}{15} + ...+\frac{1}{2021}}

The n + 1 th term of the sequence, 1, 3, 6, 10, 15, ..., 2021 is given as follows;

  • \displaystyle a_{n+1} = \mathbf{\frac{n^2 + 3 \cdot n + 2}{2}}

Therefore, for the last term we have;

  • \displaystyle 2043231= \frac{n^2 + 3 \cdot n + 2}{2}

2 × 2043231 = n² + 3·n + 2

Which gives;

n² + 3·n + 2 - 2 × 2043231 = n² + 3·n - 4086460 = 0

Which gives, the number of terms, n = 2020

\displaystyle \frac{A}{2}  = \mathbf{ 1011 \cdot  \left(\frac{1}{2} +\frac{1}{6} + \frac{1}{12}+...+\frac{1}{4086460}  \right)}

\displaystyle \frac{A}{2}  = 1011 \cdot  \left(1 - \frac{1}{2} +\frac{1}{2} -  \frac{1}{3} + \frac{1}{3}- \frac{1}{4} +...+\frac{1}{2021}-\frac{1}{2022}  \right)

Which gives;

\displaystyle \frac{A}{2}  = 1011 \cdot  \left(1 - \frac{1}{2022}  \right)

\displaystyle  A = 2 \times 1011 \cdot  \left(1 - \frac{1}{2022}  \right) = \frac{1032231}{511} \approx \mathbf{2020.022}

  • A ≈ <u>2020.022</u>

Learn more about the sum of a series here:

brainly.com/question/190295

8 0
2 years ago
Read 2 more answers
Please help please anyone please help me with this please please help
77julia77 [94]

Answer:

plleaseeeeeeeeeeeeeeeeeeeeeeeee eeeeeeeeee

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Oliver has a box of toy cars, but he is not sure how many he has. If he arranges the cars in groups of four, he has three left o
Zarrin [17]
X/4 = r3 or 3/4
x/3 = r2 or 2/3
x/5 = r3 or 3/5

we know x is not divisible by 4 3 or 5 and is less than 30.

we know the value ends in 3 or 8 from x/5 = r3

we know the value is greater than 3 from r3

so far we got 13 and 23

13 is eliminated from x/4 = r3 because it is r1 not r3

so the answer is 23




7 0
3 years ago
725 tickets were sold for a game for a total of $1,487.50. If adult tickets sold for $2.50 and children's tickets sold for $1.50
weqwewe [10]

Answer:

  • 400 adult tickets
  • 325 children's tickets

Step-by-step explanation:

Let x represent the number of adult tickets sold. Then 725-x is the number of children's tickets sold, and the total revenue is ...

  2.50x +1.50(725 -x) = 1487.50

  1.00x + 1087.50 = 1487.50 . . . . . eliminate parentheses

  x = 400 . . . . . . . . . . . . . . . . . . . . . subtract 1087.50

There were 400 adult tickets and 325 children's tickets sold.

3 0
3 years ago
Read 2 more answers
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