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Bond [772]
3 years ago
5

What number can you put in the missing spot of the domain to keep the table a function? Select all that apply.​

Mathematics
1 answer:
Bingel [31]3 years ago
5 0

Answer:

1,8 and 5,10

Step-by-step explanation:

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A large university accepts 60​% of the students who apply. Of the students the university​ accepts, 40​% actually enroll. If 30,
kykrilka [37]

Answer:

7,200

Step-by-step explanation:

Let's start by calculating how many students the university accepts. The problem says they accept 60% of the students. 60% as a decimal is 0.6. To calculate 60% of something, you multiply .60 by whatever quantity. In this case, it would be the students.

Number of accepted students = .6 * 30000 = 18,000

The university accepts 18,000 students.

Now, the next problem is that of those accepted students, we need to find out how many actually enroll. The problem says they accept 40% of the accepted students. Applying the same principle,

Number of enrolled students = .4 * 18000 = 7,200

The number of students that actually enroll is 7,200.

Alternatively, .6 * 30000 * .4 would give you the same result.

Combining the pieces together, we are asking for 60% of 30,000. Then getting 40% of that 60%.

3 0
2 years ago
An exit poll in an election is a survey taken of voters just after they have voted. One major use of exit polls has been so that
3241004551 [841]

Answer:

P(A) = 0.39

Step-by-step explanation:

We are given;

P(W|A) = 0.7

P(W|A^c ) = 0.3

We are told that 60% of the respondents said they voted for A. Thus;

P(A|W) = 60% = 0.6

Now, using the principle of drawing lots, we can be able to find the probability of the event that they are willing to participate in the exit poll which is P(W).

Thus;

P(W) = [P(W|A) × P(A)] +[P(W∣A^c) × P(A^c)]

Now, P(A^c) can be expressed as 1 - P(A)

Thus, we now have;

P(W) = [P(W|A) × P(A)] + [P(W∣A^c) × (1 - P(A)]

Plugging in the relevant values gives;

P(W) = 0.7P(A) + 0.3(1 - P(A))

P(W) = 0.7P(A) + 0.3 - 0.3P(A)

P(W) = 0.3 + 0.4P(A)

Now,using Baye's theorem, we can find an expression for P(A|W)

Thus;

P(A|W) = [P(A ∩ W)]/P(W)

This can be further expressed as;

P(A|W) = [P(A) × P(W|A)]/P(W)

Plugging in relevant values, we have;

0.6 = 0.7P(A)/(0.3 + 0.4P(A))

Cross multiply to get;

0.6(0.3 + 0.4P(A)) = 0.7P(A)

0.18 + 0.24P(A) = 0.7P(A)

0.18 = 0.7P(A) - 0.24P(A)

0.46P(A) = 0.18

P(A) = 0.18/0.46

P(A) = 0.39

7 0
3 years ago
Given that 6.00 Ghanaceasa dolar
mash [69]

Answer:

do you have options to this

4 0
2 years ago
Simplify and write in standard form (7-8i)(7-8i)<br><br>plzzzz show all work<br>​
ASHA 777 [7]
7-(8*7)+(8*6)+(8*5)+(8*4)+(8*3)+(8*2)+(8*1)=7-56+48+40+32+24+16+8= 217*217= 47089
7 0
2 years ago
Writing Polynomial Functions
vitfil [10]

Answer:

Step-by-step explanation:

If the zero occur when x={5, -2, -1} then the equation must be

(x-5)(x+2)(x+1) if expansion is desired

(x^2-3x-10)(x+1)

x^3+x^2-3x^2-3x-10x-10

x^3-2x^2-13x-10

4 0
2 years ago
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