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3 years ago

Please find the slope!! 20PTS!! WILL GIVE BRAINIEST

Mathematics

1 answer:

Anastaziya [24]3 years ago

8 0

3) .25 or 1/4

4) 1.25 or 5/4

You do rise over run to figure it out!

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This is due in 15 minutes pls help me lol thx

GaryK [48]

Answer:

ITS A

Step-by-step explanation:

PLZ GIVE BRAINLEIST

7 0

3 years ago

Read 2 more answers

A cylinder fits inside a square prism as shown. For every cross section, the ratio of the area of the circle to the area of the

kolbaska11 [484]

Answer:

Volume of cylinder = $\pi r^2h$

Step-by-step explanation:

Given : A cylinder fits inside a square prism.

To find : The volume of cylinder

Solution : Refer the attached graph.

Area of circle = $\pi r^2$

Area of square = $s^2$

Side of square = diameter of circle= $D^2$

Diameter = 2r

∴ Area of square= $2r^2=4r^2$

$\frac{Area of circle}{Area of Square}=\frac{\pi r^2}{4r^2}=\frac{\pi}{4}$

Area of circle is $\frac{\pi }{4}$ of area of square.

Volume is always = area × height

Volume of prism = Area of square × h = $4r^2h$

Volume of cylinder = Area of circle × h = $\pi r^2h$

Now, rate

$\frac{Volume of cylinder}{Volume of prism}=\frac{\pi r^2h}{4r^2h}=\frac{\pi}{4}$

⇒Volume of cylinder is $\frac{\pi }{4}$ of Volume of prism.

Volume of Cylinder = $\frac{\pi }{4}\times Volume of prism$

Volume of cylinder = $\frac{\pi }{4}\times 4r^2h$

Volume of cylinder = $\pi r^2h$

6 0

3 years ago

Read 2 more answers

Why is it necessary to use the absolute value of the difference when finding the distance on a number line, but not necessary wh

padilas [110]

Remember that the distance on a number line is given by the formula: $d=|x_{2}-x_{1}|$
where
$d$ is the distance between the points.
$x_{2}$ is the second point in the number line.
$x_{1}$ is the first point in the number line.
Now, suppose we are trying to find the distance between the points -1 and -5; our first point is -1, so $x_{1}=-1$ , and our second point is $-5$ , so $x_{2}=-5$ . Suppose we are going to find the distance between the two point without using absolute value:
$d=x_{2}-x_{1}$
$d=-5-(-1)$
$d=-5+1$
$d=-4$
Look what we have here, a negative distance! Since distances cannot be negative, we must use absolute value to always get postie distances between two point on a umber line:
$d=|x_{2}-x_{1}|$
$d=|-5-(-1)|$
$d=|-5+1|$
$d=|-4|$
$d=4$

Now, the distance between two coordinates on a plane is given by the formula: $d= \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$
$where$
$d$ is the distance between the two coordinates
$(x_{1},y_{2})$ are the coordinates of the first point
$(x_{2},y_{2})$ are the coordinates of the second point
Notice that $(x_{2}-x_{1})^2$ and $(y_{2}-y_{1})^2$ are squared, so it doesn't matter if we get a negative distance because a negative number raised to an even power (like 2) is always positive; therefore we don't need absolute value in this case because we won't ever get a negative distance.

7 0

3 years ago

What is the slope of the line through (1,-1)(1,−1)left parenthesis, 1, comma, minus, 1, right parenthesis and (5,-7)(5,−7)left p

Leona [35]

Answer:

-3/2

Step-by-step explanation:

We can find the slope between two points using

m = (y2-y1)/(x2-x1)

= (-7 - -1)/(5 - 1)

(-7+1(/(5-1)

-6/4

-3/2

5 0

3 years ago

What is the gradient of (0,3) and (1,8)

Paha777 [63]

Answer: 5/1 = 5

Step-by-step explanation:

The gradient is the slope of something. The slope = rise/run so you just do 8-3 = 5 is the rise and then 1-0 = the run so its a gradient of 5

5 0

3 years ago