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makkiz [27]
3 years ago
13

Why is it necessary to use the absolute value of the difference when finding the distance on a number line, but not necessary wh

en finding the differences of the coordinates in the coordinate plane?"
Mathematics
1 answer:
padilas [110]3 years ago
7 0
Remember that the distance on a number line is given by the formula: d=|x_{2}-x_{1}|
where 
d is the distance between the points. 
x_{2} is the second point in the number line.  
x_{1} is the first point in the number line.
Now, suppose we are trying to find the distance between the points -1 and -5; our first point is -1, so x_{1}=-1, and our second point is -5, so x_{2}=-5. Suppose we are going to find the distance between the two point without using absolute value:
d=x_{2}-x_{1}
d=-5-(-1)
d=-5+1
d=-4
Look what we have here, a negative distance! Since distances cannot be negative, we must use absolute value to always get postie distances between two point on a umber line:
d=|x_{2}-x_{1}|
d=|-5-(-1)|
d=|-5+1|
d=|-4|
d=4 

Now, the distance between two coordinates on a plane is given by the formula: d= \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}
where
d is the distance between the two coordinates
(x_{1},y_{2}) are the coordinates of the first point
(x_{2},y_{2}) are the coordinates of the second point 
Notice that (x_{2}-x_{1})^2 and (y_{2}-y_{1})^2 are squared, so it doesn't matter if we get a negative distance because a negative number raised to an even power (like 2) is always positive; therefore we don't need absolute value in this case because we won't ever get a negative distance. 


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ycow [4]

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3 years ago
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RoseWind [281]
This is an excellent practice for the solution of quadratic equations.

1*36=36  => (1,36)
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tankabanditka [31]

Answer:

1.778 times more or 16/9 times more

Step-by-step explanation:

Given:

- Mirror 1: D_1 = 8''

- Mirror 2: D_2 = 6"

Find:

Compare the light gathering power of an 8" primary mirror with a 6" primary mirror. The 8" mirror has how much light gathering power?

Solution:

- The light gathering power of a mirror (LGP) is proportional to the Area of the objects:

                                           LGP ∝ A

- Whereas, Area is proportional to the squared of the diameter i.e an area of a circle:

                                           A ∝ D^2

- Hence,                              LGP ∝ D^2

- Now compare the two diameters given:

                                           LGP_1 ∝ (D_1)^2

                                           LGP ∝ (D_2)^2

- Take a ratio of both:

                           LGP_1/LGP_2 ∝ (D_1)^2 / (D_2)^2

- Plug in the values:

                               LGP_1/LGP_2 ∝ (8)^2 / (6)^2

- Compute:             LGP_1/LGP_2 ∝ 16/9 ≅ 1.778 times more

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Answer:

155.25 grams

Step-by-step explanation:

40 = X(½^(9/4.6))

X = 40 ÷ (½^(9/4.6))

X = 155.25 grams

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