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3 years ago

Hallppp!!

Mathematics

1 answer:

Juli2301 [7.4K]3 years ago

3 0

Answer:

Modeling Real Events

1000 times in 10 second= 100 times per second
Hence 100 × 12 = 1200 times
$\frac{7250}{100} = 72.5$

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Suppose we have a right triangle with legs of length a and b and hypotenuse of length c. Suppose b=3 and c=5. Then a= , For the

ANTONII [103]

Answer:

Length of right-angle triangle 'a' = 4

$sin(A) = \frac{opposite side}{Hypotenuse} = \frac{a}{c} = \frac{4}{5}$

$cos(A) = \frac{Adjacent side}{Hypotenuse} = \frac{b}{c} = \frac{3}{5}$

$tan(A) = \frac{opposite side}{Adjacent side} = \frac{a}{b} = \frac{4}{3}$

Step-by-step explanation:

Step(i):-

Given b = 3 and hypotenuse c = 5

Given ΔABC is a right angle triangle

By using pythagoras theorem

c² = a² + b²

⇒ a² = c² - b²

⇒ a² = 5²-3²

=25 - 9

a² = 16

⇒ a = √16 = 4

The sides of right angle triangle a = 4 ,b = 3 and c = 5

Step(ii):-

$sin(A) = \frac{opposite side}{Hypotenuse} = \frac{a}{c} = \frac{4}{5}$

$cos(A) = \frac{Adjacent side}{Hypotenuse} = \frac{b}{c} = \frac{3}{5}$

$tan(A) = \frac{opposite side}{Adjacent side} = \frac{a}{b} = \frac{4}{3}$

7 0

3 years ago

The heaviest dinosaur is estimated to have welghed 2.8 x 10^5 pounds. The average car weighs about 4 x 10^3 pounds.

34kurt

Answer:

Step-by-step explanation:

Apparently, you want the ratio of the weights:

(dino weight)/(car weight) = (2.8×10^5)/(4×10^3)

= (2.8/4)×10^(5-3) = 0.7×10^2 = 0.7×100

= 70

The heaviest dinosaur weighed about 70 times the weight of an average car.

_____

Your calculator can do arithmetic in scientific notation. So can any spreadsheet.

The applicable rule of exponents is ...

(10^a)/(10^b) = 10^(a-b)

4 0

3 years ago

4.b) A strawberry order costs $241.50. How many pounds did the grocer order?

hram777 [196]

You need more info :/

7 0

3 years ago

Read 2 more answers

Use the rules of significant figures to find the answer to the addition problem S= 25.4+14+16.67+3.903

xenn [34]

S=59.973 all you have to do now is round it. So the real answer is S=60. All i did was add up all the numbers.
$25.4 + 16.67 = 42.07 + 3.903 = 45.973 + 14 = 59.973$

6 0

3 years ago

Patricia baked some cupcakes for sale. she put half of the cupcakes equally into 6 big boxes and the other half equally into sma

mojhsa [17]

Answer:

The answer is given below

Step-by-step explanation:

Let us assume Patricia baked x number of cakes. She put half of the cupcakes (i.e x/2) equally into 6 big boxes.

6 big boxes contained $\frac{x}{2}$ cakes, therefore 1 big box would contain $\frac{x}{2}/6=\frac{x}{12}$ cakes.

Let us assume she put the other half into 14 small boxes, therefore each small box would contain $\frac{x}{2}/14=\frac{x}{28}$ cakes.

There were 45 cupcakes in 3 big boxes and 8 small boxes altogether. That is: $3(\frac{x}{12} )+8(\frac{x}{28})=45\\ 84x+96x=15120\\180x=15120\\x=84$

Therefore Patricia baked 84 cup cakes

She sold all the small boxes and collected $189, i.e she sold 14 small box for $189. Each small box = $189/14 = $13.5

6 0

3 years ago