Divide the number of respondents saying it was useful by the total number
63/85 = 0.74
thinking you braindead mf
Answer:
The equation can define y as a function of x and it also can define x as a function of y.
Step-by-step explanation:
A relation is a function if and only if each value in the domain is mapped into only one value in the range.
So, if we have:
f(x₀) = A
and, for the same input x₀:
f(x₀) = B
Then this is not a function, because it is mapping the element x₀ into two different outputs.
Now we want to see it:
x + y = 27
defines y as a function of x.
if we isolate y, we get:
y = f(x) = 27 - x
Now, this is a linear equation, so for each value of x we will find an unique correspondent value of y, so yes, this is a function.
Now we also want to check if:
x + y = 27
defines x as a function of y.
So now we need to isolate x to get:
x = f(y) = 27 - y
Again, this is a linear equation, there are no values of y such that f(y) has two different values. Then this is a function.
If you want to check if your answer is correct, expanding it all out will help!
(x-6)(x+2)=0 <-- Use FOIL tactic
x²+2x-6x-12=0
x²-4x-12=0
As you can see, this is identical to the initial equation given. The x values would be 6 and -2, as seen from the factored equation.
Hope I helped :)
<h3><em>refer</em><em> to</em><em> the</em><em> attachment</em></h3><h2><u>hope</u><u> it</u><u> helps</u></h2><h2 />
