Answer:
Step-by-step explanation:
In this particular case we have the following system of equations:
y
=
−
3
x
+
4
[
E
q
.
1
]
x
+
4
y
=
−
6
[
E
q
.
2
]
Substituting
[
E
q
.
1
]
in
[
E
q
.
2
]
:
x
+
4
(
−
3
x
+
4
)
=
−
6
Applying the distributive property on the left side:
x
−
12
x
+
16
=
−
6
Simplifying
:
−
11
x
=
−
22
Solving for
y
:
x
=
−
22
−
11
=
2
Substituting
x
=
2
in
[
E
q
.
1
]
:
y
=
−
3
(
2
)
+
4
=
−
2
Therefore
, the solutions are
x
=
2
and
y
=
−
2
Answer:
End Behavior of a Function. The end behavior of a polynomial function is the behavior of the graph of f( x ) as x approaches positive infinity or negative infinity. The degree and the leading coefficient of a polynomial function determine the end behavior of the graph.
Step-by-step explanation:
Answer:
A. 42½ units
Step-by-step explanation:
the volume = 5×2×4¼ = 10×4¼ = 42½
Answer:
see explanation
Step-by-step explanation:
(h + k)(x) = h(x) + k(x), thus
h(x) + k(x)
= x² + 1 + x - 2 = x² + x - 1 , then
(h + k)(2) = 2² + 2 - 1 = 4 + 2 - 1 = 5
----------------------------------------------------
(h - k)(x) = h(x) - k(x), thus
h(x) - k(x)
= x² + 1 - (x - 2) = x² + 1 - x + 2 = x² - x + 3, then
(h - k)(3) = 3² - 3 + 3 = 9 - 3 + 3 = 9
-----------------------------------------------------
h(2) = 2² + 1 = 4 + 1 = 5
k(3) = 3 - 2 = 1
Thus
3h(2) + 2k(3)
= 3(5) + 2(1) = 15 + 2 = 17
