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3 years ago

5.1.2 Exam: Semester 2 Exam

Mathematics

1 answer:

Nikolay [14]3 years ago

8 0

Answer:

See attached picture to view the graph

Step-by-step explanation:

Start by analyzing how this average idea works:

If only one member goes to the trip, it will cost him/her $1000+$200 = $1200.

If two members go to the trip, then they will share the cost as per the following: ($1000+ $200 + $200 = $1400) which they will be dividing into two people, thus costing each of them $700.

Notice that the general function that represents such average will be given by: $f(x) = \frac{1000+200x}{x}$

Plot such function in the two dimensional plane, and you will get the asymptotic behavior shown in the attached image.

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Ross has to fill up a 300 gallon tank. There are already 75

stepan [7]

Answer: He needs 9 hours to finish the task.

Step-by-step explanation:

Hi, first we have to subtract the gallons of water already in the tank (75) to the total capacity of the tank (300).

300-75 = 225

He needs to fill 225 gallons.

Since the pump Ross uses can fill 25 gallons of water per hour, the proportion is :

25 g / 1h

For 225 gallons:

225 g / x hours

Solving for x

25/1 = 225/x

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3 years ago

A circle has an area of 324╥ cm². What is the radius?

Stolb23 [73]

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3 years ago

Read 2 more answers

Security A rounds every 2 minutes and 20 seconds in the gate 1. Security B rounds every 1 minute and 40 seconds in the gate 2. I

Elden [556K]

Answer:

$Time = 11\frac{2}{3}\ min$

Step-by-step explanation:

Given

$Security\ A = 2\ mins, 20\ secs$

$Security\ B = 1\ mins, 40\ secs$

Required

After how many minutes, will they round together

First, convert the given time to minutes

$Security\ A = 2\ mins, 20\ secs$

$Security\ A = 2\ mins+ 20\ secs$

$Security\ A = 2\ mins+ \frac{20}{60}\ min$

$Security\ A = 2\ mins+ \frac{1}{3}\ min$

$Security\ A = 2\frac{1}{3}\ min$

$Security\ B = 1\ mins, 40\ secs$

$Security\ B = 1\ mins+ 40\ secs$

$Security\ B = 1\ mins+ \frac{40}{60}\ min$

$Security\ B = 1\frac{2}{3}\ min$

So, we have:

$Security\ A = 2\frac{1}{3}\ min$

$Security\ B = 1\frac{2}{3}\ min$

List out the multiples of the time of both security personnel take round.

$Security\ A = 2\frac{1}{3}min,\ 4\frac{2}{3}min,\ 7min,\ 9\frac{1}{3}min,\ 11\frac{2}{3}min...$

$Security\ B = 1\frac{2}{3}min,\ 3\frac{1}{3}min,\ 5min,\ 6\frac{2}{3}min,\ 8\frac{1}{3}min,\ 10min\ ,11\frac{2}{3}min,...$

In the above lists, the common time is:

$Time = 11\frac{2}{3}\ min$

This implies that they go on round after $11\frac{2}{3}\ min$

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3 years ago

Please help, math work

NikAS [45]

Y = 3x + 5 because the slope is 3/1 and 0 = 5

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3 years ago

Need help solving this 10x+32

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10x+32=0
10x=-32
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