Answer:
-16 and -14
14 and 16
Step-by-step explanation:
Let's say x is the smaller integer and x+2 is the larger integer. Their product is 224.
x (x + 2) = 224
x² + 2x = 224
Complete the square and solve for x.
x² + 2x + 1 = 225
(x + 1)² = 225
x + 1 = ±15
x = -16 or 14
x + 2 = -14 or 16
So the integers are either -16 and -14, or 14 and 16.
What's the question you're asking
Given the equation 4(3b + 2)² = 64,
dividing both sides of the equation by 4, we have
(3b + 2)² = 16 and getting the square root of both sides,
(3b + 2) = 4 and (3b + 2) = -4
We can solve for b for each equation and have
3b = 2 | 3b = -6
b = 2/3 | b = -2
Therefore, the values of b are 2/3 and -2 and from the choices, the answer is <span>A: b = 2/3 and b = -2.</span>
Answer:
y = 8x + 21
Step-by-step explanation:
