1. We don't know the meaning of "{There is a box image here}".
If you're dealing with congruent figures, match the corresponding letters in the name of the figure:
.. E F G H
.. Q R S T
If you're concerned with QT (1st and 4th letters), you need to look at EH (1st and 4th letters).
If EFGH ≅ QRST, then QT = EH = 6.3.
2. LM = ST = 5.2
Assuming x is the missing angle, and knowing that complimentary means 90, subtract 90-73 to get 17.
Answer:
43.82 mph
266.67 feet
Step-by-step explanation:
Given :
S = √30fl
S = speed of car
f = drag Coefficient
l = Length of skid mark
If f = 0.8 ; l = 80 feets
s = √30fl
s = √(30*0.8*80)
s = √1920
s = 43.817
s = 43.82 mph
B.)
s = 80 mph
f = 0.8
s = √30fl
80 = √30*0.8*l
80 = √24l
Square both sides
80² = 24l
6400 = 24l
l = 6400/24
l = 266.67 feets
Solve for the bracelet first.
x represents number of beads for bracelet
So it would be number of beads for the bracelet + number of beads for necklace (5x) and they both equal 192
x + 5x = 192
Then you would add the x and 5x.<br />6x = 192
Now all you have to do is divide by 6 on both sides.
6× ÷ 6 = 192 ÷ 6
You know have the number of beads it takes for a bracelet.
x = 32
to get the necklace all you need to do is multiply it by 5 because you need 5 times more for the necklace.
32 × 5
total beads needed is 160.
160
x+5x=192
6×=192
6x÷6=192÷6
x=32
necklace needs 32x5
beads per necklace is 160
Answer:
Step-by-step explanation:
Parameterize the ellipse as (acos∙,bsin∙). Take points P:=(acosp,bsinp) and Q:=(acosq,bsinq) on the ellipse, with midpoint M:=(P+Q)/2.
If |PQ|=2k, then
a2(cosp−cosq)2+b2(sinp−sinq)2=4k2
The coordinates of M are
xy==a2(cosp+cosq)b2(sinp+sinq)
